Q: Is the square root of 36 an integer?

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The square root of 3 is not an integer.

No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106

Yes, a perfect square is a number that has an integer square root.

Square: 36 x 36 = 1296 Square root: √36 = 6

No. The square root of a positive integer can only be an integer, or an irrational number.

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Yes.

No, a square number is one that has an integer for a square root and the square root of 36 is 5.83. The closest square number to 34 is 36 which is 6^2

The square root of an integer is a CYCLOTOMIC integer.

Negative 64 is the square root of an integer. The square root of -64 is not an integer.

Because it is an integer, 6. The underlying reason is that all of its prime factors are expressed as squares. 36 = 22 x 32If all prime factors do not have an even exponent, the square root will not be an integer.

no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...

The square root of 3 is not an integer.

Is the square root of a 100 is a integer

No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106

No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.

-- If the square root is an integer, then add ' 1 ' to it. -- If the square root is not an integer, then there isn't any.

Square root of 25 = 251/2 = 5, which is an integer. So the square root of 25 is integer.