Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
Yes.
x2 - y2 + 9x - 9y =(x2 + 9x) - (y2 + 9y) =x(x + 9) - y(y + 9)================================Another way to go after it:x2 - y2 + 9x - 9y =(x2 - y2) + 9x - 9y =(x + y) (x - y) + 9 (x - y) =(x + y + 9) (x - y)
2x+3y=13 3x-y=3 x=2
f(x) or y = 6x + 4Well, y= mx+ b This function is simplified already.
33/4
2
m
it is (x-y)(x-y) :)
x is y plus 25% of y.
p(x) = x4 + 2x3 + x2 + 8x - 12When you go to graph this function, you make 'y' = p(x) .At the y-intercept, 'x' is zero.There, y = -12 .
Your question is like this:X+Y=15, X-Y=5, (X x Y)-X+Y= ?According to my calculations, X=10 and Y=5, therefore (X x Y)-X+Y= 45.
A negative minus a negative turns the latter into a plus positive,for example -6 minus -3 would be :-6 ++ 3 = -3A minus negative always turns into a plus positive...To get more Specific:Suppose x and y are two POSITIVE numbers so that -x and -y are negative. Then a negative minus a negative = (-x) - (-y) = -x +yIf x > y the answer is negativeIf x = y the answer is zeroIf x < y the answer is positive
You can tell if an equation is a function if for any x value that you put into the function, you get only one y value. The equation you asked about is the equation of a line. It is a function.
-x+y = 1 -2+y = -2 y = 1+x y = -2+2 => y = 0 By sustituting the values of x and y can be found x = -1 and y = 0 Remember that a minus from a minus is equal to a plus. So - -1+0 = 1
Locate the turning point(s) for the following functions. (a) y=x3-x2 -3x + 5 3
No. It is an equation. A function would link the variable x to another variable - possibly denoted by y. It is a relationship between two (or more) variables.