Just do it systematically, START WITH 0123 0124 0125 etc 0129 now 1234 1235 keep going! There are 10 numbers from 0 to 9. So the number of combinations of 4 digits numbers is 30.
10C4 = 10!/[(10 - 4)!4!] = 10!/(6!4!) = (10 x 9 x 8 x 7 x 6!)/(6! x 4 x 3 x 2 x 1)= 10 x 3 = 30
list of all 4 digit codes without repeating using only number 1-9?
To convert a one digit repeating decimal, make a fraction of that digit over 9, so 55/99 = 5/9 You can convert any repeating digits by putting them over the same number of 9s.
The number of 3-digit numbers with no repeated digits is simply 10x9x8 = 720, if you allow, for example, 012 as a 3-digit number. There are 10 digits, any of which might be the first digit. The second digit can be any digit except the digit that was used for the first digit, leaving 9 possibilities. The third digit then has 8 possibilities, since it can't be the same as the first or second digit. The actual number of possible area codes will be lower, because there are additional restrictions on the number combinations for a valid area code. For example, in North America (USA, Canada, etc.), the first digit of an area code cannot be 0 or 1 and the middle digit cannot be 9.
first digit time second digit and second digit times first digit then repeat
999-111=888 888 3 digit numbers can be made with numbers between 1 - 9
The 3 digit numbers under 500 are 100 through 499.
6
1,023,456,789
5040
24680
9,876,543,210 9876543210
9875.
There are 840 4-digit combinations without repeating any digit in the combinations.
Assuming whole numbers and a leading zero does not count: 10,234,567
18, if leading 0s are disallowed.
24
256
93876