Oh, dude, you wanna list out all the 4-digit combinations without repeating digits from 0 to 9? That's like 10 choose 4, which is 10! / (4!(10-4)!), which equals 210. So, there are 210 unique 4-digit combinations you can make using numbers 0 to 9 without repeating any digits. Cool, right?
To form a four-digit number without repeating any digits from 56789, we need to choose 4 different digits out of the 5 available. This can be done in 5 choose 4 ways, which is equal to 5! / (4! * (5-4)!) = 5 ways. Therefore, there are 5 four-digit numbers that can be formed out of 56789 without repeating any digits.
To convert a one digit repeating decimal, make a fraction of that digit over 9, so 55/99 = 5/9 You can convert any repeating digits by putting them over the same number of 9s.
The number of 3-digit numbers with no repeated digits is simply 10x9x8 = 720, if you allow, for example, 012 as a 3-digit number. There are 10 digits, any of which might be the first digit. The second digit can be any digit except the digit that was used for the first digit, leaving 9 possibilities. The third digit then has 8 possibilities, since it can't be the same as the first or second digit. The actual number of possible area codes will be lower, because there are additional restrictions on the number combinations for a valid area code. For example, in North America (USA, Canada, etc.), the first digit of an area code cannot be 0 or 1 and the middle digit cannot be 9.
first digit time second digit and second digit times first digit then repeat
999-111=888 888 3 digit numbers can be made with numbers between 1 - 9
6
5040
1,023,456,789
24680
9,876,543,210 9876543210
9875.
There are 840 4-digit combinations without repeating any digit in the combinations.
Assuming whole numbers and a leading zero does not count: 10,234,567
256
24
93876
93,876