List of all 4 digit combintions without repeating using only numbers 0-9?

Answer 1

Just do it systematically, START WITH 0123 0124 0125 etc 0129 now 1234 1235 keep going! There are 10 numbers from 0 to 9. So the number of combinations of 4 digits numbers is 30.

10C4 = 10!/[(10 - 4)!4!] = 10!/(6!4!) = (10 x 9 x 8 x 7 x 6!)/(6! x 4 x 3 x 2 x 1)= 10 x 3 = 30

Answer 2

Oh, dude, you wanna list out all the 4-digit combinations without repeating digits from 0 to 9? That's like 10 choose 4, which is 10! / (4!(10-4)!), which equals 210. So, there are 210 unique 4-digit combinations you can make using numbers 0 to 9 without repeating any digits. Cool, right?

Answer 3

To calculate the total number of unique 4-digit combinations without repeating using numbers 0-9, we can use the permutation formula. Since we are selecting 4 digits from a set of 10 without replacement, the formula is 10P4 = 10! / (10-4)! = 10 x 9 x 8 x 7 = 5040. Therefore, there are 5040 possible 4-digit combinations using numbers 0-9 without repetition.

Answer 4

list of all 4 digit codes without repeating using only number 1-9?