Q: How do you factor 100x2-81 equals 0?

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2(m - 25)

-(h - 4)(h + 8)

If a polynomial has factors x-6 and x-3 it will equal 0 if either factor equals 0 since the other factor then would be multiplied by 0. ie. 0 * (x-6)=0 and 0 * (x-3)=0. so x=3 or 6

0 = 2m^2 - 2m + 36 0 = 2(m^2 - m + 18) 0 = m^2 - m + 18

4x2-4x-3=0 can be written as (2x-3)(2x+1)=0 Anything times by 0 equals 0 ( the zero property of multiplication) therefore we need to make each one of these terms in brackets equal to 0. so 2x-3=0 giving x=3/2 and 2x+1=0 giving x=-1/2

Related questions

Yes.

a(-14-a) = 0 so a = 0 or a = -14

4(x + 1) = 0.

D is the choice that is not true.

Zero Product Property

2(m - 25)

x squared -2x-3 equals 0 is the same as (x + 1)(x - 3) = 0

Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.

(n + 4)(n - 4)

(x + 6)(x - 6)

No, there cannot be a zero in any scale factor.

3x3 -3x2 - 48x - 60 = 0 simply factor out a 3... 3(x3 - x2 - 16x - 20) = 0