0
What else can I help you with?
What is the midpoint between the points 4 1 and 10 9?
Let (x1, y1) = (4, 1) and (x2, y2) = (10, 9)The midpoint formula: [(x2 - x1)/2, (y2 - y1)/2]Substitute the given coordinates of the two points into formula:[(x2 - x1)/2, (y2 - y1)/2]= [(10 - 4)/2, (9 - 1)/2]=(6/2, 8/2)= (3, 4)Thus the midpoint is (3, 4).
Find the distance between the points -10 8 and -2 -7?
Use Pythagoras' Theorem: calculate the square root of ((difference of x-coordinates)2 + (difference of y-coordinates)2).
What is 10 less than 8?
10 less than 8 is (10>8) If you are putting it into an sentence(problem) it would be 8-10 (= -2)!
What is the domain for (10 8) (14 4) (4 0) (13 0) (-16 13) (17 -14)?
Domain includes all of the x-coordinates, which are 10, 14, 4, 13, -16, and 17. So the domain would be the set {-16, 4, 10, 13, 14, 17}
What is the perpendicular bisector equation of the line segment whose endpoints are at -4 -10 and 8 -1 on the Cartesian plane?
Endpoints: (-4, -10) and (8, -1) Midpoint: (2, -5.5) Slope: 3/4 Perpendicular slope: -4/3 Perpendicular equation: y --5.5 = -4/3(x-2) => 3y = -4x -8.5 Perpendicular bisector equation in its general form: 4x+3y+8.5 = 0
If the midpoint of xy is located at the origin and one endpoint of this segment has coordinates of -8 10 what are the coordinates of the other endpoint?
The other end point is (8,-10).
Find the coordinates of the midpoint of the segment whose endpoints are H(8 2) and K(6 10)?
The midpoint is at (7, 6)
The midpoint of the coordinates (9 11) and (7 8) is?
To find the midpoint, you find the mean (average) of each direction's coordinates. The average of the x coordinates is (9+7)/2 = 8. The average of y coordinates is (11+8)/2 = 9.5, So the midpoint is (8,9.5). This same method works for 3 and higher dimensions.
What are the coordinates of the midpoint between the points 4 5 and 12 5?
midpoint: (8, 5)
How to find the endpoint if the midpoint and a endpoint is already given?
Ok.The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2]So for instance if your coordinates were endpoint : (-8,10) and the Midpoint: (-2,6)By substituting the given How_do_you_find_an_endpoint_of_a_line_if_you_are_given_an_endpoint_and_the_midpointinto the formula we have:(x1 + -8)/2 = -2 and (y1 + 10)/2 = 6x1 - 8 = -4 and y1 + 10 = 12x1 -8 + 8 = -4 + 8 and y1 + 10 - 10 = 12 - 10x1 = 4 and y1 = 2so the endpoints coordinates are ( 4, 2)
How do you find an endpoint of a line if you are given an endpoint and the midpoint?
Ok.The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2]So for instance if your coordinates were endpoint : (-8,10) and the Midpoint: (-2,6)By substituting the given values into the formula we have:(x1 + -8)/2 = -2 and (y1 + 10)/2 = 6x1 - 8 = -4 and y1 + 10 = 12x1 -8 + 8 = -4 + 8 and y1 + 10 - 10 = 12 - 10x1 = 4 and y1 = 2so the endpoints coordinates are ( 4, 2)
If the midpoint of a horizontal line segment with a length of 8 is 3 -2 then the coordinates of its endpoints are?
If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
Distance between 8 -13 and 1 -7 Midpoint between 8 -13 and 1 -7?
For the distance, use the Pythagorean formula. For the midpoint, take the average of the x-coordinates, and the average of the y-coordinates.
What is the midpoint of -23 and 8-7 coordinates?
If you mean: (-2, 3) and (8, -7) then the midpont is (3, -2)
What is the midpoint of a segment whose endpoints are 12 7 and 8 -11?
The midpoint is at: (10, -2)
M is the midpoint of JK The coordinates of J are 6 3 and the coordinates of M are -3 4 find the coordinates of K?
M is the midpoint and J and K are the endpoints.J has coordinates (6,3) and M has coordinates (-3,4) Let (x,y) be the coordinates of KThen ((6+x)/2, (3+y)/2)=(-3,4)So 1/2( 6+x)=-3 so 6+x=-6 and x=-121/2(3+y)=4 so 3+y=8 and y=5Then K=(-12,5)We check that M is in fact the midpoint of J=(6,3) and K=(-12,5)(-6/2, 8/2)=(-3,4)=M
What is the midpoint of the segment from Point A 6 3 to Point B 8 1?
The mid point is at the mean average of each of the coordinates: The midpoint between A (6,3) and and B (8,1) is (6+8/2, 3+1/2) = (7, 2)
