The answer is (8,6). I just drew a graph and found the slope then I used the slope once going downwards from the midpoint
Let (x1, y1) = (4, 1) and (x2, y2) = (10, 9)The midpoint formula: [(x2 - x1)/2, (y2 - y1)/2]Substitute the given coordinates of the two points into formula:[(x2 - x1)/2, (y2 - y1)/2]= [(10 - 4)/2, (9 - 1)/2]=(6/2, 8/2)= (3, 4)Thus the midpoint is (3, 4).
Use Pythagoras' Theorem: calculate the square root of ((difference of x-coordinates)2 + (difference of y-coordinates)2).
Domain includes all of the x-coordinates, which are 10, 14, 4, 13, -16, and 17. So the domain would be the set {-16, 4, 10, 13, 14, 17}
Endpoints: (-4, -10) and (8, -1) Midpoint: (2, -5.5) Slope: 3/4 Perpendicular slope: -4/3 Perpendicular equation: y --5.5 = -4/3(x-2) => 3y = -4x -8.5 Perpendicular bisector equation in its general form: 4x+3y+8.5 = 0
If you mean points of (5, 8) and (3, 9) then the slope works out as -1/2
The other end point is (8,-10).
The midpoint is at (7, 6)
To find the midpoint, you find the mean (average) of each direction's coordinates. The average of the x coordinates is (9+7)/2 = 8. The average of y coordinates is (11+8)/2 = 9.5, So the midpoint is (8,9.5). This same method works for 3 and higher dimensions.
midpoint: (8, 5)
Ok.The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2]So for instance if your coordinates were endpoint : (-8,10) and the Midpoint: (-2,6)By substituting the given values into the formula we have:(x1 + -8)/2 = -2 and (y1 + 10)/2 = 6x1 - 8 = -4 and y1 + 10 = 12x1 -8 + 8 = -4 + 8 and y1 + 10 - 10 = 12 - 10x1 = 4 and y1 = 2so the endpoints coordinates are ( 4, 2)
Ok.The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2]So for instance if your coordinates were endpoint : (-8,10) and the Midpoint: (-2,6)By substituting the given How_do_you_find_an_endpoint_of_a_line_if_you_are_given_an_endpoint_and_the_midpointinto the formula we have:(x1 + -8)/2 = -2 and (y1 + 10)/2 = 6x1 - 8 = -4 and y1 + 10 = 12x1 -8 + 8 = -4 + 8 and y1 + 10 - 10 = 12 - 10x1 = 4 and y1 = 2so the endpoints coordinates are ( 4, 2)
If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
For the distance, use the Pythagorean formula. For the midpoint, take the average of the x-coordinates, and the average of the y-coordinates.
If you mean: (-2, 3) and (8, -7) then the midpont is (3, -2)
The midpoint is at: (10, -2)
M is the midpoint and J and K are the endpoints.J has coordinates (6,3) and M has coordinates (-3,4) Let (x,y) be the coordinates of KThen ((6+x)/2, (3+y)/2)=(-3,4)So 1/2( 6+x)=-3 so 6+x=-6 and x=-121/2(3+y)=4 so 3+y=8 and y=5Then K=(-12,5)We check that M is in fact the midpoint of J=(6,3) and K=(-12,5)(-6/2, 8/2)=(-3,4)=M
The mid point is at the mean average of each of the coordinates: The midpoint between A (6,3) and and B (8,1) is (6+8/2, 3+1/2) = (7, 2)