Let (x1, y1) = (4, 1) and (x2, y2) = (10, 9)
The midpoint formula: [(x2 - x1)/2, (y2 - y1)/2]
Substitute the given coordinates of the two points into formula:
[(x2 - x1)/2, (y2 - y1)/2]
= [(10 - 4)/2, (9 - 1)/2]
=(6/2, 8/2)
= (3, 4)
Thus the midpoint is (3, 4).
-- The x-coordinate of the midpoint is the average of the x-coordinates of the end-points. -- The y-coordinate of the midpoint is the average of the y-coordinates of the end-points. -- The average of two numbers is 1/2 of (the first number plus the second number).
If you mean end points of (3.2, 2.5) and (1.6, -4.5) then the midpoint is (2.4, -1)
End points: (10, -4) and (2, 2) Midpoint: (6, -1) Distance from (6, -1) to (10, -4) = 5 Distance from (6, -1) to (2, 2) = 5 Equation of the circle: (x-6)^2 +(y+1)^2 = 25
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 = -13/2(x-0.5) => 2y-4 = -13x+6.5 => 2y = -13x+10.5
(-0.5, 1.5) is.
If you mean points of (-1, 10) and (9, -1) then the midpoint is (4, 4.5)
If you mean points of (10, 1) and (4, 7) then the midpoint is at (7, 4)
If you mean: (10, -3) and (1, 0) then the midpoint is at (5.5, -1.5)
If you mean points of (-2, 5) and (4, 8) then the midpoint is at (1, 6.5)
Points:(4, 3) and (10, -5) Midpoint: (4+10)/2, (3-5)/2 = (7, -1)
The midpoint is (2,3)
-1 + -2 = -3-3/2 = -1.54 + -9 = -5-5/2 = -2.5So the midpoint = (-11/2, -21/2)
Points: (-1, 5) and (-6, -2) Midpoint: (-3.5, 1.5)
Points: (-1, 5) and (-6, -2)Midpoint: (-3.5, 1.5)
If you mean points of (-1, 5) and (5, 5) then the midpoint is at (2, 5)
End points: (3.2, 2.5) and (1.6, -4.5) Midpoint: ( 2.4, -1)