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Let (x1, y1) = (4, 1) and (x2, y2) = (10, 9)
The midpoint formula: [(x2 - x1)/2, (y2 - y1)/2]
Substitute the given coordinates of the two points into formula:
[(x2 - x1)/2, (y2 - y1)/2]
= [(10 - 4)/2, (9 - 1)/2]
=(6/2, 8/2)
= (3, 4)
Thus the midpoint is (3, 4).
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How do you find the midpoint of line segments with given endpoints are given -5 20 -10 15?
-- The x-coordinate of the midpoint is the average of the x-coordinates of the end-points. -- The y-coordinate of the midpoint is the average of the y-coordinates of the end-points. -- The average of two numbers is 1/2 of (the first number plus the second number).
What is the midpoint pf the line segment with endpoints(3.22.5)and(1.6-4.5)?
If you mean end points of (3.2, 2.5) and (1.6, -4.5) then the midpoint is (2.4, -1)
What is the equation of a circle whose diameter end points are at 10 -4 and 2 2 on the Cartesian plane?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) Distance from (6, -1) to (10, -4) = 5 Distance from (6, -1) to (2, 2) = 5 Equation of the circle: (x-6)^2 +(y+1)^2 = 25
Find the distance between points -6 1 and 10 -8?
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
What is the distance between the points 3 5 and 1 8?
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
