0
Fir0,4,4,6,8,14 st of all make sure the numbers are in rank order. In this case they are,
0,4,4,6,8,14
RANGE is the difference between the highest and lowest numbers. 14 - 0 = 14 The range./
MODE is the most frequent term. In this case it is '4'
MEDIAN is the absolute middle term. Since there are two terms in the middle, 4 & 6 , we add and divide by '2'/ Hence (4+6) / 2 = 5 The median
MEAN is the sum of all the terms divided by the number of terms
Hence ( 0+4+4+6+8+14) / 6 =>
36 6 = 6 The mean
NB Althpough there is a 'zero' term, it must be included in the addition and the number of terms.
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Which two numbers have a mean of ten and a range of 8?
6 + 14
What is the median of 9 13 15 16 20 17 15 14 10 15 17 13?
Median = 15
What is a set of 5 positive numbers that has a median 10 and mean 14?
One way to do this would be to assume that four the numbers are 10 (this guarantees that the median is 10.) Now all that is left is to find the fifth number that would make the mean to be 14. We need the average of the numbers to be 14, so we can write the equation: (10 + 10 +10 + 10 + x)/5 = 14where x is the number we need to find. The equation can be simplified:(40 + x)/5 = 148 + x/5 = 14x/5 = 6x = 30.So one possible set of numbers is {10, 10, 10, 10, 30}.(There are many other possible sets as well.)
If a set of data has 5 numbers has a range of 9 a mode of 9 a median of 11 and a mean of 12 what are the 5 numbers?
This is a logical puzzle. You can read the statement this way:There are five numbers.The highest number is 8 greater than the lowest numberThe number that repeats the most is 9The number in the middle of the set is 11The average of the numbers is 12We know that there are five numbers [statement #1], so let's call them a, b, c, d and e, in ascending order.Given: (a + b + c + d + e) / 5 = 12 [statement #5]∴ a + b + c + d + e = 60Given: c = 11 [statement #4]∴ a + b + 11 + d + e = 60If the middle number is 11, and the most repetitious number is 9 [statement #3], then a and b must both equal 9.∴ 9 + 9 + 11 + d + e = 60Given: e = a + 8 [statement #2], and the knowledge that a = 9, we know then that e = 9 + 8, or 17:∴ 9 + 9 + 11 + d + 17 = 60and with that, we can calculate the value of our final number, d:∴ d = 60 - 9 - 9 - 11 - 17∴ d = 60 - 46∴ d = 14So the set of data is:{9, 9, 11, 14, 17}You can quickly check these results by using the original statements on them:"... has a range of 9 ..." - correct. 9 through 17 inclusive is indeed a range of 9."... a mode of 9 ..." - correct, that is the most frequently occurring number."... a median of 11 ..." - correct, that is our original number"... a mean of 12 ..." (9 + 9 + 11 + 14 + 17) / 5 = 12, - correct, that is our mean.
How do you find the median when you have two int?
When you find the median you are trying to find the middle of a set of numbers. If you line the numbers up in numerical order and count one off on each side multiple times, you will get to the middle. However, if you have only two numbers or two numbers in the middle, you would add those two numbers together and then divide by two. For example: 2, 4, 14, 27, 65, 83 First, you would count off 2 and 83 then 4 and 65. You would be left with 14 and 27 in the middle. You would add 14 and 27 to get 41. Then, you would divide 41 by two to get 20.5 which would be your median.
