Any 2 of 12 is (12 x 11)/2 = 66. Any 2 from 6 is (6 x 5)/2 = 15 so the probability is 15 out of 66 ie 0.227 or 22.7%
5/6
10
The probability is 15/25 = 3/5
Here are 10 students getting honors credits in a class, and they make up 20% of the class. How do we find the number of students in the class? Let's look. We have a class, and 20% of the class are getting honors credit, and that turns out to be 10 students. Now we can generate a formula that we can use to discover our answer. Let's assign letters to the things we know or are finding out. Nclass = number of students in the class. Nhonors = number of honors students in the class. And Nhonors = 10 students. Nclass x 20% = 10 students 20% = 20/100ths (because % = hundredths) or 0.20 or just 0.2 for simplicity. Nclass x .2 = 10 students Now divide both sides by .2 so the .2 will cancel out (or drop out) on the left side of the equation and we'll have isolated the answer we are looking for, which is Nclass. Nclass = 10 students divided by .2 Nclass = 10/.2 students = 50 students There are 50 students in the class. As .2 equals 2/10 or 1/5, we can find 1/5th of 50 just by thinking about it to check our work. And 1/5th of 50 equals 10, which is in agreement with the information we were given in the problem.
30
cause its fun
It depends on how big the class is.
The probability is 15/25 = 3/5
The probability is the number of girls divided by the number of students, so 12/22, or 6/11
10
judged by top GPA of the students class rank and act/sat scores
.9^27, or approximately .058 = 5.8%
The probability of this is based heavily on whether or not said best friend is even in the class. If both are in, it's a 1/870 chance.Ê
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
I am not going to help you cheat in math class!!!!!!!!!!!!!
The probability is 15/25 = 3/5
13 out of 20
The probability that a randomly chosen student is a woman can be calculated by dividing the number of women by the total number of students in the class. In this case, there are 13 women and 31 total students, so the probability is 13/31, which simplifies to approximately 0.419 or 41.9%.