The probability is 15/25 = 3/5
The probability is the number of girls divided by the number of students, so 12/22, or 6/11
50% of 12 male students = 6 25% of 4 female students = 1 So in total 7 students go for pizza. The probability that a randomly selected student will be female is 1/7 or 14%.
21.5%
No. The probability that a continuous random variable takes a specific value is always zero.
It depends on what the random variable is, what its domain is, what its probability distribution function is. The probability that a randomly selected random variable has a value between 40 and 60 is probably quite close to zero.
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
The probability is 15/25 = 3/5
To find the probability that the second student chosen is a boy given that the first student chosen is a boy, we first note that there are 22 students total (13 girls and 9 boys). If the first student chosen is a boy, there will then be 8 boys and 13 girls remaining, making a total of 21 students left. Therefore, the probability that the second student is a boy is the number of remaining boys (8) divided by the total remaining students (21), which gives us a probability of ( \frac{8}{21} ).
The probability is 10 percent.
There is only one girl out of 12 students so the probability that the girl is selected is 1/12.
P( a student getting an A) = 5/20=1/4 There are 3 students. The probability that all three got an A is (1/4)(1/4)(1/4)=1/64.
If a student is picked at random what is the probability that he/she received an A on his/her fina?
1/12 =0.08333... ≈ 8.3%
The probability of this is based heavily on whether or not said best friend is even in the class. If both are in, it's a 1/870 chance.Ê
"Playing cards" are chosen at random.
The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.
3/4