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π2 = 9.8676

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15y ago

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How do you manually calculate i raised to the power of i?

by euler: i=ei(pi)/2 therifore ii = (ei(pi)/2)i=ei^2(pi)/2=e-(pi)/2 ~0.208


What is the cubic root of pi squared multiplied by pi?

[pi^(1/3)]^2 * pi = pi^(2/3) * pi = pi^(5/3) The answer is the cubic root of pi to the fifth power.


How can you make rational of i power i?

It is NOT rational, but it IS real.Start with Euler's formula: e^ix = cos(x) + i*sin(x) for all x.When x = pi/2,e^(i*pi/2) = cos(pi/2) + i*sin(pi/2) = 0 + i*1 = ior i = e^(i*pi/2)Raising both sides to the power i givesi^i = e^[i*(i*pi/2)] = e^[i*i*pi/2]and since i*i = -1,i^i = e^(-pi/2) = 0.20788, approx.


How do you manually calculate i to the power of i?

i (taken to be sqrt(-1) for this question) requires that you know a bit about writing complex numbers. i = e^(i*pi/2) so i^i = (e^(i*pi/2))^i which equals e^(i*i*pi/2) since i*i = -1 we get e^(-pi/2) so i^i = e^(-pi/2) which is roughly .207879576


What is pi to the 5th power?

Pi to the 5th power is approximately 306.019684785


What is V equals pi times 2 to the second power times 120?

Assuming pi to be 3.14, 2^2 = 4(120) = 480*3.14 = 1507.2


Can anyone prove i to the power i where i is square root of -1 is rational?

Nobody can prove it because it is not true. It is a real number, though. eix = cos(x) + i*sin(x) Therefore ei*pi/2 = cos(pi/2) + i*sin(pi/2) = 0 + i*1 = i Raising both sides to the ith power, (ei*pi/2)i = ii So that ii = ei*i*pi/2 = e-pi/2 = 0.2079. Gelfond proved that the above value is irrational [transcendental, actually].


What is pi squared to the one half power?

it is pi..... wait no it isnt.....pi squared to the one half power is not pi...


What is the difference between circle and Pi?

This is PI, pi = 3.14159265...... A circle is the round thing, like your pies! The area of a circle is measured using (Pi)(radius to the power of 2). Circumfrance of a circle is (Pi)(Diameter of circle).


What is the answer of iota power iota?

The expression ( i^\iota ) can be evaluated using Euler's formula. Specifically, ( i ) can be expressed as ( e^{i\pi/2} ), so ( i^\iota = (e^{i\pi/2})^\iota = e^{-\pi/2} ). Therefore, the value of ( i^\iota ) is ( e^{-\pi/2} ), which is a real number approximately equal to 0.20788.


How do you work out the area if given the circumference?

Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)


What is 2 pi over 2?

2 pi / 2 = pi.

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