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What is the value of pi by 2?
The value of Pi is 3.14 so the value of Pi by 2 is 6.28.
Can the circumference and the area of a circle both have the same answer?
C=2(pi)r A=(pi)r2 If C=A, then 2(pi)r=(pi)r2. Divide both sides by r: 2(pi)=(pi)r. Divide both sides by (pi): 2=r. Therefore, if the radius of a circle is 2 ft., the circumference is 2 sq. ft.
If the circumference of a circle doubles the radius?
IMPOSSIBLE circumference = 2*pi*radius if circumference = 2*radius: 2*radius=2*pi*radius 2*radius/(2*radius)=2*pi*radius/(2*radius) 1=pi pi= 1 therefore it is impossible to have a circumference that is twice that of the radius
What is pi to the power of infinity?
Infinity.
Is pi the same as the square root of 2?
No. Pi is roughly 3.1416. The square root of 2 is roughly 1.4142. Pi is about 122% bigger than the square root of 2. The square root of 2 is about 55% smaller than pi.
How do you manually calculate i raised to the power of i?
by euler: i=ei(pi)/2 therifore ii = (ei(pi)/2)i=ei^2(pi)/2=e-(pi)/2 ~0.208
What is the cubic root of pi squared multiplied by pi?
[pi^(1/3)]^2 * pi = pi^(2/3) * pi = pi^(5/3) The answer is the cubic root of pi to the fifth power.
How can you make rational of i power i?
It is NOT rational, but it IS real.Start with Euler's formula: e^ix = cos(x) + i*sin(x) for all x.When x = pi/2,e^(i*pi/2) = cos(pi/2) + i*sin(pi/2) = 0 + i*1 = ior i = e^(i*pi/2)Raising both sides to the power i givesi^i = e^[i*(i*pi/2)] = e^[i*i*pi/2]and since i*i = -1,i^i = e^(-pi/2) = 0.20788, approx.
How do you manually calculate i to the power of i?
i (taken to be sqrt(-1) for this question) requires that you know a bit about writing complex numbers. i = e^(i*pi/2) so i^i = (e^(i*pi/2))^i which equals e^(i*i*pi/2) since i*i = -1 we get e^(-pi/2) so i^i = e^(-pi/2) which is roughly .207879576
Can anyone prove i to the power i where i is square root of -1 is rational?
Nobody can prove it because it is not true. It is a real number, though. eix = cos(x) + i*sin(x) Therefore ei*pi/2 = cos(pi/2) + i*sin(pi/2) = 0 + i*1 = i Raising both sides to the ith power, (ei*pi/2)i = ii So that ii = ei*i*pi/2 = e-pi/2 = 0.2079. Gelfond proved that the above value is irrational [transcendental, actually].
What is V equals pi times 2 to the second power times 120?
Assuming pi to be 3.14, 2^2 = 4(120) = 480*3.14 = 1507.2
What is pi to the 5th power?
Pi to the 5th power is approximately 306.019684785
Why does a lens with a 2-cm diameter have 4 times the light-gathering power of a 1-cm lens?
The light-gathering power of a lens is proportional to its area, which is determined by the formula for the area of a circle, ( A = \pi r^2 ). A 1-cm diameter lens has a radius of 0.5 cm, giving it an area of ( \pi (0.5)^2 = \frac{\pi}{4} ) cm². In contrast, a 2-cm diameter lens has a radius of 1 cm, resulting in an area of ( \pi (1)^2 = \pi ) cm². Since ( \pi ) is four times ( \frac{\pi}{4} ), the 2-cm lens indeed has four times the light-gathering power of the 1-cm lens.
What is pi squared to the one half power?
it is pi..... wait no it isnt.....pi squared to the one half power is not pi...
What is the difference between circle and Pi?
This is PI, pi = 3.14159265...... A circle is the round thing, like your pies! The area of a circle is measured using (Pi)(radius to the power of 2). Circumfrance of a circle is (Pi)(Diameter of circle).
What is the answer of iota power iota?
The expression ( i^\iota ) can be evaluated using Euler's formula. Specifically, ( i ) can be expressed as ( e^{i\pi/2} ), so ( i^\iota = (e^{i\pi/2})^\iota = e^{-\pi/2} ). Therefore, the value of ( i^\iota ) is ( e^{-\pi/2} ), which is a real number approximately equal to 0.20788.
How do you work out the area if given the circumference?
Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)
