it is 2squared times 15 (or 60)
-3-4-5=-12
(8 - 3) x (4 - 3) = 5 x 1 = 5
x^(-5/3) = 4 1/x^(5/3) = 4 x^(5/3) = 1/4 [x^(5/3)]^(3/5) = (1/4)^(3/5) x = 1/4^(3/5) or, x = 4^(-3/5) Check: x^(-5/3) = 4 [4^(-3/5)]^(-5/3) = 4 ? 4 ^(15/15) = 4 ? 4^1 = 4 ? 4 = 4
the product of 4x5=20 is 2
225 = 3 * 3 * 5 * 5
-3-4-5=-12
The product of 4 and 3 is (4 \times 3 = 12). The sum of 4 and 3 is (4 + 3 = 7). To find how much greater the product is than the sum, we subtract the sum from the product: (12 - 7 = 5). Therefore, the product is 5 greater than the sum.
As a product of its prime factors: 3*3*5*5 = 225
(5+4)-(3x3)=0
To find the product of 3, 4, and 5, you simply multiply the numbers together. Start by multiplying 3 and 4, which equals 12. Then, multiply that result by 5: 12 x 5 equals 60. Therefore, the product of 3, 4, and 5 is 60.
(8 - 3) x (4 - 3) = 5 x 1 = 5
3*4*5=60 3+4+5=12
12-7 =5
(4+5) - (2 x 3) = 3
Meaningless question. I would guess that the questioner has typed 'product' when he means 'remainder'.
15 x 8 = 120
3x3=9 5+4=9 9-9=0