(8 - 3) x (4 - 3) = 5 x 1 = 5
it is 2squared times 15 (or 60)
x^(-5/3) = 4 1/x^(5/3) = 4 x^(5/3) = 1/4 [x^(5/3)]^(3/5) = (1/4)^(3/5) x = 1/4^(3/5) or, x = 4^(-3/5) Check: x^(-5/3) = 4 [4^(-3/5)]^(-5/3) = 4 ? 4 ^(15/15) = 4 ? 4^1 = 4 ? 4 = 4
5*43 = 5*(40 + 3) = 5*40 + 5*3 = 200 + 15 = 215
3x + 4y = 5To find the x-intercept, let x = 03(0) + 4y = 54y = 5y = 5/4The line passes through (0, 5/4), so y-intercept is 5/4.To find x-intercept, let y = 03x + 4(0) = 53x = 5x = 5/3The line passes through (5/3, 0), so x-intercept is 5/3.Plot (0, 5/4) and (5/3, 0). Draw a straight line through them.Or,3x + 4y = 53x - 3x + 4y = 5 - 3x4y = -3x + 54y/4 = (-3x + 5)/4y = (-3/4)x + 5/4So the slope will be -3/4 and the y-intercept is 5/4; (0, 5/4)We find the x-intercept when y = 0, so0 = (-3/4)x + 5/40 - 5/4 = (-3/4)x + 5/4 - 5/4-5/4 = (-3/4)x(-5/4)/(-3/4) = [(-3/4)x]/(-3/4)5/3 = x ; (5/3, 0)Thus, the line passes through the points (0, 5/4) and (5/3, 0).
(6)(5)(4)(3) = 360
Probably 2*3*4*5*6*7 = 5040
If three is subtracted from the product to get 17, the product must be 20. Then find what number can be multiplied by 5 to get 20. The answer is 4.
As a product of its prime factors: 3*3*5*5 = 225
(5+4)-(3x3)=0
(8 - 3) x (4 - 3) = 5 x 1 = 5
No. The smallest 4 primes are 2, 3, 5 and 7 and their product is 210.
3*4*5=60 3+4+5=12
12-7 =5
(4+5) - (2 x 3) = 3
Meaningless question. I would guess that the questioner has typed 'product' when he means 'remainder'.
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