(8 - 3) x (4 - 3) = 5 x 1 = 5
it is 2squared times 15 (or 60)
x^(-5/3) = 4 1/x^(5/3) = 4 x^(5/3) = 1/4 [x^(5/3)]^(3/5) = (1/4)^(3/5) x = 1/4^(3/5) or, x = 4^(-3/5) Check: x^(-5/3) = 4 [4^(-3/5)]^(-5/3) = 4 ? 4 ^(15/15) = 4 ? 4^1 = 4 ? 4 = 4
5*43 = 5*(40 + 3) = 5*40 + 5*3 = 200 + 15 = 215
find the inverse of (1,-5)(3,-3)(4,-2)
(6)(5)(4)(3) = 360
Probably 2*3*4*5*6*7 = 5040
If three is subtracted from the product to get 17, the product must be 20. Then find what number can be multiplied by 5 to get 20. The answer is 4.
As a product of its prime factors: 3*3*5*5 = 225
(5+4)-(3x3)=0
(8 - 3) x (4 - 3) = 5 x 1 = 5
12-7 =5
3*4*5=60 3+4+5=12
No. The smallest 4 primes are 2, 3, 5 and 7 and their product is 210.
the product of 4 and 5 is 20
25
15 x 8 = 120