No. An equation must be equal to something, that's why its called an equation. 15x = 60 is an equation, in which case x equals 4
x=100
ln 60 = a
You cannot solve 1 linear equation in 2 unknown variables. You need at least two independent equations.
cos60= 1/2 sin60=1.732/2
15x = 60 The variable is x.
It looks like an incomplete equation.
-53
"Wat" is the variable.
65
No. An equation must be equal to something, that's why its called an equation. 15x = 60 is an equation, in which case x equals 4
60 x 1.5 is 90
Doesn't have integer roots. Quadratic formula gives roots as 3.71 and -5.38.
This is a quadratic expression in x. It cannot be solved because it is an expression: there is no equation to solve. Furthermore, the discriminant for the quadratic = (-10)2 - 4*3*(-5) = 100+60 = 160 which is not a square number. There are, therefore no rational factors. While it would be possible to give irrational factors, factorising a quadratic into linear terms containing irrational numbers is rarely useful.
x=100
-80
Let the width be x and the length be y: xy = 60 2x+2y = 38 Divide all terns in the bottom equation by 2: xy = 60 x+y = 19 => x = 19-y Substitute the value of x in the bottom equation into the top equation: (19-y)y = 60 19y-y2 = 60 Rearrange the equation into a quadratic: -y2+19y-60 = 0 Solve by factoring or with the help of the quadratic equation formula: (-y+4)(y-15) = 0 So y = 15 or y = 4 it must be the former because it's larger Therefore: width = 4 cm and length = 15 cm