Let's try a proof by contradiction (because it isn't rational). Try and follow along the best you can.
√2 = p/q
2 = p2/q2
2q2 = p2
This means that 2q2 (an even number) is equal to another number squared. But this means that p is even, because p2 is even, and only an even number sqaured is an even number. Lets replace p with 2b (because its twice a number because it's even).
IMMA DO THE THINGS THAT I WANNA DO, I AIN'T GOTTA THING TO PROVE TO YOU. I EAT MY CANDY WITH THE PORK AND BEANS!
TO BE CONTINUED
The square root of 2 is an irrational number
that depends on the number. sqrt(2) is irrational, sqrt(4)=2 is rational
it is rational
It is equal to 21/2 which is a rational number
The square root of 29 is an irrational number.
The square root of 2 is an irrational number
No, the square root of an irrational number is not always rational. In fact, the square root of an irrational number is typically also irrational. For example, the square root of 2, which is an irrational number, is itself irrational. However, there are exceptions, such as the square root of a perfect square of an irrational number, which can be rational.
The square roots of 2 and 3 are irrational but not transcendent.
no it is an irrational number
It is rational. The root of a perfect square, such as 4, is rational; the root of any positive integer that is not a perfect square is an irrational number.
1, 2 are rational and square root of 2 and pi are irrational.
irrational
irrational
that depends on the number. sqrt(2) is irrational, sqrt(4)=2 is rational
It is irrational
Square root of 10 is irrational.
No; √2 is irrational.