Show how root 29 is represented
First, you calculate it to the desired number of decimals. Then you place it on the number line in the usual manner.
12 and 13
The square root of a negative number is considered an imaginary number, denoted as "i". In this case, the square root of -3 would be √(-3) = √3 * i. Therefore, the square root of -3 is not a real number, as real numbers are those that can be represented on the number line without involving "i".
Sometimes the square root of a positive number can be irrational, as in the square root of 2 (which is a non-perfect square number), but sometimes it is a rational number, as in the square root of 25 (which is a perfect square number).
The number 3 is the square root of the number 9 !
First, you calculate it to the desired number of decimals. Then you place it on the number line in the usual manner.
By root, I think you mean square root. The square root of 2 is approx. 1.414. The square root of 9 = 3, so this goes exactly at 3 on the number line. Square root 2 will be less than 1/2 way between 1 and 2 on the number line.
Eight to the square root of two is 18.930500992570284227768534002147.
friends,root 10 is according to our pythagores thoream.root 10=square of 3 and square of 1 can be represented on a number line.
This can not be done. Every non-negative number on the number line is the square root of its square. You would have to mark every number from zero on.
I would show it at location 1.732 , even if I was allowed to use Pythagoras.
You don't
Oh, what a happy little question! To represent the square root of 3 on the number line, you simply find where it falls between whole numbers. Since the square root of 3 is between 1 and 2, you can place it around 1.7 on the number line with a little tick mark and a smile. Remember, there are no mistakes, just happy little accidents in math!
The square root of 66 is a little bit greater than 8. So, plotted on a number line, it would be just to the right of the number 8.
12 and 13
To represent the square root of 11.5 on a number line, we first need to approximate the value. The square root of 11.5 is approximately 3.39. On the number line, locate the whole number 3 and then estimate the position of 3.39 between 3 and 4. Mark this point on the number line to represent the square root of 11.5.
√16=4