In this case you want to group the terms so they have at least two terms in common.
First step group and rewrite it:
abc + a'bc + a'b'c' + a'b'c + ab'c' + abc' =
Use the rule Identities x(y+z)=xy+xz:
bc(a+a') + a'b'(c'+c) + ac'(b'+b) =
Use the rule Identities x+x'=1:
bc (1) + a'b'(1) + ac'(1) =
Use the rule Identities x(1) = x:
bc+a'b'+ac'
an example of an algebra equation would be: 1/3(15+6a)4 read out loud would be: one-third times the quantity of 15 plus six A times 4. this is a basic algebra problem. very easy
In Boolean algebra, 1 + 1 is not "1 plus 1", it is "1 or 1". Since 1 is like true and 0 is like false, this is like asking "of the two values 1 and 1, is one of them a 1?", or asking "of the to values true and true, is one of them true?". Because there is at least one 1, the expression is 1 (true). Other examples: 1 + 0 = 1 (There is at least one 1). 0 + 0 = 0 (There is no 1).
z + 8 - 2 is an expression, not an equation. An expression cannot be solved. At best, you can simplify it to z + 6.
Looking at this as an algebra equation, x + 82 = 180, all you need to do is isolate x. To do this, subtract 82 from both sides of the equation to get x = 98.
3x
1. With boolean algebra, 1 + n is always equal to 1, no matter what the value of n is.
Your equation cannot be solved. So we simplify using fun algebra! 4b + b = 5b
According to the Law of Absorption, A+(A*B) = A. Boolean B is "absorbed" by A.Similarly, A*(A+B) = A.
18
If you simplify the equation (s+t+s) the answer is 2s+t
Because the 'plus sign' ( + ) in Boolean algebra does not mean the same thing as it does in arithmetic. In the shorthand of Boolean logic operations, the plus sign is used to mean ' OR ' .
It is not an equation because it's an algebraic expression
It is an equation.
That's an equation where x = 5
The simple form of the equation 5 - 9 + (-1) is -5.
it is not possible to simplify this equation so the answer would just be,14+21c
9x2+9x-12 All I can do is simplify this. I can't solve it unless turn this expression into an equation.