what is the solution of x-5y=10 and 2x-10y=20
2 would be the coeeficient the coefficient is the number before the variable
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
(5x -3x) (2y +8y) 2x + 10y
x = 2, y = 1
2(x - 5y)
what is the solution of x-5y=10 and 2x-10y=20
-2x-10y-12+3xy=4Put all x's to the other side and the ones with y's on the other:-10y+3xy=4+2x+12-10y+3xy=16+2xNow you factor a y from the side with the y's:y(-10+3x)=16+2xDivide both sides by (-10+3x):y=(16+2x)/(-10+3x)
52
Write out equation - 10y - 5x= - 20 Negate equation 10y + 5x = 20 Isolate y variable 10y = - 5x + 20 Divide equation by 10 y= -1/2x + 2
(5x-9)(2x-1) when factored
(2, 1)
Assume the expression is 2x + 10y = 20.x-intercept occurs where y = 0.y-intercept occurs where x = 0.Let's work on each part of the problem:X-interceptLet y = 0. Then:2x + 10(0) = 202x = 20x = 20/2x = 10So the x-intercept is (10,0)Y-interceptLet x = 0. Then:2(0) + 10y = 2010y = 20y = 20/10y = 2So the y-intercept is (0,2).
Treat it as a simultaneous equation question: -2x-10y = -12 3x+y = 4 Multiply all terms in the bottom equation by 10 in order to eliminate y: -2x-10y = -12 30x+10y = 40 Add both equations together: 28x+0 = 28 Divide both sides of the equation by 28 to find the value of x: x = 1 Substitute the value of x into the original equations to find the value of y: x = 1 and y = 1
2 would be the coeeficient the coefficient is the number before the variable
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
(5x -3x) (2y +8y) 2x + 10y