55x + (-3) = 53x + 7
can be written as
55x - 3 = 53x + 7
subtract 53x from both sides
2x - 3 = 7
add three to both sides
2x = 10
divided both sides by 2
x = 5
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5x - y = 55x - 3y = 15from the first equation:5x = 5 + y , substitute it in the second equation:5 + y - 3y = 155 -2y = 15-2y = 15 - 5-2y = 10y = -5Now,solve for x :5x = 5 +y5x = 5 -5 = zerox = zero
x will be the time in hours, so your equation is 55x+48x=49You can add the like terms together to get 103x=49You can divide by 103 to get x=49/103, or about 0.4757281 hours, or 28 minutes and 32.62116 seconds.
If the slopes of the lines are negative reciprocals, then the lines are perpendicular.2x - 5y = -3 subtract 2x to both sides-5y = -2x - 3 divide both sides by -5y = (2/5)x +3/55x + 2y = 6 subtract 5x to both sides2y = -5x + 6 divide both sides by 2y = (-5/2)x + 3Yes, the lines are perpendicular.