5x - y = 55x - 3y = 15from the first equation:5x = 5 + y , substitute it in the second equation:5 + y - 3y = 155 -2y = 15-2y = 15 - 5-2y = 10y = -5Now,solve for x :5x = 5 +y5x = 5 -5 = zerox = zero
x will be the time in hours, so your equation is 55x+48x=49You can add the like terms together to get 103x=49You can divide by 103 to get x=49/103, or about 0.4757281 hours, or 28 minutes and 32.62116 seconds.
If the slopes of the lines are negative reciprocals, then the lines are perpendicular.2x - 5y = -3 subtract 2x to both sides-5y = -2x - 3 divide both sides by -5y = (2/5)x +3/55x + 2y = 6 subtract 5x to both sides2y = -5x + 6 divide both sides by 2y = (-5/2)x + 3Yes, the lines are perpendicular.
7-5x=10-(6x+7) 7-5x=-60x-70 +5x +5x 7=-55x-70 +70 +70 77=-55x Divide -55 -1.4 = x
20 + x = 55x = 55 -20x= 35
you cant solve but you can simplify -55x
so...50+55x+28??? then it would be 78+55x because you cant add them since they aren't like terms.
If you mean solve for X: 3x + 52x + 1 = 0 55x = -1 x = -0.02
x is equivalent to 3.6545, having 45 repetetive. With this multuplied by 55 and added 10 (4 plus 6) equals -191
-5x^2 - 55x - 120
3/5 + 5x/2 = 8Multiply each term by 53 + 25x/2 = 40Multiply each term by 26 + 25x = 8025x = 80 - 625x = 74x = 74 / 25OR3/5 + 5x/2 = 85x/2 = 8 - 3/55x/2 = 40/5 - 3/55x/2 = 37/55x = 37/5 * 25x = 74/5x = 74/5 * 1/5x = 74/25
0
2(3x^2 + 55x - 485)
x2 + 55x - 700 = (x + 20)(x + 35) 2x2x5x5x71,700=6992,350=3484,175=1715,140=1357,100=9310,70=6014,50=3620,35=1525,28=3If you were doing x^2+55x+700 then it would be factorable with 20 and 35 but with a negative in front of the 700 it is prime.
66x^3 - 36x^2 = 6x^2(11x - 6) 55x - 30 = 5(11x - 6) 66x^3 - 36x^2 + 55x - 30 = (6x^2 + 5)(11x - 6)