7x+43y=123 ..............(1)
43x+37y=117 ..............(2)
ADD EQN (1)AND(2)
WE GET 80X + 80Y = 240, WHICH WHEN REDUCED IS X + Y = 3 ........................(3)
SUBRACTING EQN (1) AND (2) WE GET
-6X + 6Y = 6, WHICH WHEN REDUCED IS (-X + Y = 1) ........................(4)
ADDING EQN (3) AND (4)
X + Y = 3
-X + Y = 1
WE GET 2Y = 4
SO Y = 2
SUBSTITUTING Y = 2 IN EQN (3) WE GET
X + 2 = 3
SO X = 1
THEREFORE X= 1 AND Y = 2 IS THE SOLUTION FOR THE PAIR OF LINEAR EQUATIONS.
5x + 3y = -7x = 43 - 8y5x + 3y = -75(43 - 8y) + 3y = -7215 - 40y + 3y = -7215 - 37y = -7215 -215 -37y = -7 - 215-37y = -222-37y/-37 = -222/-37y = 6x = 43 - 8yx = 43 - 8(6)x = 43 - 48x = -5Thus, (-5, 6) is the solution of the given system of the linear equations.
Set variable x equal to number of cars and variable y equal to number of days. You should get the equation 1.50x + 37y Hope this helps!
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Use the variable of x for the number of 37 cent stamps. Use the variable of y for the 23 cent stamps. We know that .37x + .23y = 4.85 We also know that x+y = 15 Subtract y from both sides of the equation. So x = 15 -y Substitute (15-y) in the first equation. .37(15-y) + .23y = 4.85 5.55 -.37y + .23y = 4.85 5.55 - .14y = 4.85 5.55 = 4.85 + .14y 5.55 - 4.85 = .14y .7 = .14y .7/.14 = y 5 = y Therefore x = 10 .37(10) + .23(5) = 4.85
3y - 37 = 2x2 - 18x3y = 2x2 - 18x + 37y = (2/3)x2 - 6x + (37/3)The graph is a parabola.Shanice outshines Manuel.
yes he dose her name is Telina Thomas she is 37y with 5k 3 boy 2 twingirls think he need to know thisA.S.A.P she live in HEMET
Answer:22, 15.Solution:Suppose the first number is x, second one is y, then x + y = 37, x - y = 7.adding these equations:x + y = 37+x - y = 7_____________2 x + 0 = 44x = 44/2 = 22now substitute in first equation:22 + y = 37y = 37 - 22y = 15so the numbers are: 22 and 15.
Equations: 2x+5y-3z = 4 and 3x-2y = 0 and 7x-4y-5z = -23 their solutions are:- 5*(2x+5y-3z =4) => 10x+25y-15z = 20 3*(7x-4y-5z = -23) => 21x-12y-15z = -69 Subtracting the above: -11x+37y = 89 thus eliminating z 3*(-11x+37y = 89) => -33x+111y = 267 11*(3x-2y = 0) => 33x-22y = 0 Adding the above: 89y = 267 thus eliminating x If: 89y = 267 then y = 267/89 => 3 So by substitution: x = 2, y = 3 and z = 5 Check: (2*2)+(5*3)-(3*5) = 4 Check: (3*2)-(2*3) = 0 Check: (7*2)-(4*3)-(5*5) = -23