5x + 3y = -7
x = 43 - 8y
5x + 3y = -7
5(43 - 8y) + 3y = -7
215 - 40y + 3y = -7
215 - 37y = -7
215 -215 -37y = -7 - 215
-37y = -222
-37y/-37 = -222/-37
y = 6
x = 43 - 8y
x = 43 - 8(6)
x = 43 - 48
x = -5
Thus, (-5, 6) is the solution of the given system of the linear equations.
(2,3)
x+2(x+3) = 12 x+2x+6 = 12 x+2x = 12-6 3x = 6 x = 2 and y = 5
If: x+y = 8 and 2x-y = 5 Then by adding the equations together: 3x = 13 or x = 13/3 By substitution into the original equations: x = 13/3 and y = 11/3
17
x=6y-4x=-2y+28Substitute (6y-4) for x in the second equation and solve for y:6y-4=-2y+288y=32y=4Then solve for x:x=6(4)-4=20(20,4)
(2,3)
If: x+y = 4 and y = 2x+1 Then: 4-x = 2x+1 => 3 = 3x => 1 = x So by substitution: x = 1 and y = 3
2x-3y=13
-2
how do you use the substitution method for this problem 2x-3y=-2 4x+y=24
2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.
This is not Calculus.y=7(Already solved)substiute y=7 into y=8xtherefore 7 = 8xtherefore x = 7/8
x+2(x+3) = 12 x+2x+6 = 12 x+2x = 12-6 3x = 6 x = 2 and y = 5
y=16 x= -4
16
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".
You'd need another equation to sub in