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-2x+3y+14 and x+2y+7 1. x+2y+7=0 2. x= -2y-7 3. (substitute new equation in for x) -2(-2y-7)+3y+14=0 4. (distribute) 4y+14+3y+14=0 5. (combine like terms) 7y+28=0 6. (subtract 28) 7y= -28 7. (28 divided by 7 to solve for y) y= -4 8. (substitute -4 value for y) x+2(-4)+7 9. (solve for x value) x-8+7 x-1=0 x=1 10. (answer check) -2(1)+3(-4)+14= 0 (1)+2(-4)+7=0
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What is the solution to this system of equations 6x-3y -33 2x y -1 using substituition?
If you mean: 6x-3y = -33 and 2x+y = -1 Then solving the simultaneous equations by substitution: x = -3 and y = 5
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