What is the sum of the exterior angles of a 23 gon
find the sum of the measures of the interior angles of 13-gon.
The sum of the interior angles of a n-gon is (n-2)*180 degrees. So the sum of the int angles of a 25-gon is 23*180 = 4140 degrees. If the 25-gon is regular, then each of its interior angles is equal. In this case, it is 4140/25 = 165.6 degrees.
The sum of the exterior angles of a polygon, with any number of sides, is 360 degrees.
The sum of the interior angles add up to 3240 degrees.
15-gon??? assuming you mean a pendedecagon, here is your answer: 2,340 degrees
156 Degrees
The sum of the interior angles of a 15-gon is (15-2)x180 degree which is 13x180 degrees or 2340 degrees.
The interior angles of a 15-agon add up to 2340 degrees
The sum of the interior angles of a n-gon is (n-2)*180 degrees. Convexity does not matter. So for a 17-gon, the sum would be 15*180 = 2700 degrees.
156 Degrees
The sum of the interior angles of a n-gon is (n-2)*180 degrees. So the sum of the interior angles of a 15-gon would be (15-2)*180 degrees = 2340 degrees. If the 15-gon is regular then all its interior angles are equal. In that case, each would be 2340/15 = 156 degrees.
the sum of the interior angles of a 35-gon.
The sum of the exterior angles of ANY polygon is 360 degrees.
The sum of interior angle ( Sum-of-interior-angles-n-gon) of n-gon is:If we have a ,Then
The sum of the interior angles of an n-gon are 180*(n-2) degrees. Whether the polygon is regular or not makes no difference. When n = 15, this is 180*13 = 2340 degrees.
The exterior angles of any polygon add up to 360.