angle
If you know any two sides of a triangle (and know that one of the angles is a right angle), you can calculate the third side. Also, if you know the third side of a triangle, you can check whether the angle opposite the hypothenuse is a right angle or not.
Suppose the lengths of the legs is L metres and the hypotenuse is H metres. Then, by Pythagoras, L2 + L2 = H2 that is, 2L2 = H2 Or L2 = H2/2 so that L = H/sqrt(2)
Well, to put it simply, the Pythagorean theorem is an equation to find the measurement of a side of a triangle.Algebra is basically equations, and geometry is the study and measurement of shapes. The equation is a+b=c.
Being a right- angled triangle apply Pythagoras. h^2 = a^2 + b^2 Hence b^(2) = h^2 - a^2 b^(2) = ( h + a)(h - a) b^2 = (122 + 22)( 122 - 22) b^2 = 144(100) b^2 = 14400 b = sqrt(14400) = 120 .
It states that for any right angle triangle that its hypotenuse when squared is equal to the sum of its squared sides.
hypotenuse
hypotenuse
Hypotenuse which is part of Pythagoras theorem :D
They are described by the famous Pythagoras theorem, if "a" and "b" are the legs and "h" the hypotenuse, then h x h = (a x a) + (b x b) Also a = h x sinB (where B is the internal angle (of the triangle) between the hypotenuse and side b and b = h x sinA (where A is the internal angle (of the triangle) between the hypotenuse and side a
Use Pythagoras' Theorem : In a right angled triangle the square of the hypotenuse is equal to the sum of the squares of the other two sides. Let H be the hypotenuse then :- H2 = 152 + 82 = 225 + 64 = 289 Then H = √289 = 17cm
By Pythagoras h^2 = a^2 + b^2 Substituting h^2 = 12^(2) + 5^(2) h^2 = 144 + 25 h^2 = 169 h = sqrt(169) h = 13
The important thing here is that it's a right triangle. Since it is, you can use the Pythagorean theorem. The Pythagorean theorem is as follows... (Length of leg)^2 + (Length of leg)^2 = (Hypotenuse)^2 6^2 + 8^2 = h^2 36 + 64 + h^2 100 = h^2 (Now extract the root from both sides) 10=h
From the Pythagorean theorem, if the unknown hypotenuse is called h, h2 = 162 + 122, or h = sq rt (256 + 144) = 20 units. (This is a 3-4-5 triangle enlarged by a factor of 4.)
half, hypotenuse
In a isosceles triangle, the altitude is also a median. If we draw the altitude, then two congruent right triangles are formed, with hypotenuse length of 12m and base length 5 m (10/2). So the length of hypotenuse, by the Pythagorean theorem is h^2 = 12^2 - 5^2 h = √(144 - 25) h = √119 h ≈ 10.9
According to Pythagoras's theorem, the square on the hypotenuse is equal to the sum of the squares on the other two sides. So, h2 = 92 + 122 = 81 + 144 = 225 so h= sqrt (225) and since a negative length does not make sense, h = 15 feet.
In a right triangle, the altitude with the hypotenuse as base divides the hypotenuse into two sections p and q. If we denote the length of the altitude by h, we have the relation h2 = p*q (Euklids altitutude theorem). So, first draw the square root of 2 as the diagonal of a square with side length 1, then construct a right triangle with p=1 and q= sqrt(2) by using the Thales theorem and its altitude will be fourth root of 2 according to Euclids theorem.