Divide the sum of the three consecutive numbers by 3: 75/3=25. The smallest of these numbers will be one less than 25 and the largest will be one more than 25, so the three consecutive numbers will be 24, 25, and 26.
There is no set of 8 consecutive whole numbers whose sum is 75.
75 and 76
The numbers are 37 and 38.
Let's represent the two consecutive numbers as x and x+1. The sum of these two numbers is x + (x+1) = 2x + 1. Given that the sum is 75, we have the equation 2x + 1 = 75. Solving for x, we find x = 37. Therefore, the two consecutive numbers are 37 and 38, and their sum is indeed 75.
They are 24, 25 and 26.
There is no set of 8 consecutive whole numbers whose sum is 75.
13 + 14 + 15 + 16 + 17 = 75
Let the nu bers be n,n+1, n+2, & n+3 Hence n + n+1 + n+2 + n+3 = 75 4n + 6 = 75 4n = 69 n = 69/4 n = 17 remainder '1' So there are no four whole number that sum to 75.
75 is a whole number. Two consecutive whole numbers can't lie between a single whole number. It's possible you want to know about the square root of 75 which lies between 8 and 9, but we can't know that for sure.
24 + 25 + 26 = 75
75 and 76
74 + 75
5625
The numbers are 37 and 38.
The numbers are 73, 74, 75, 76 and 77.
Whole no are the number which begin from 0 Factors of 75 are 5x5x3 All the numbers are whole numbers.
Let's represent the two consecutive numbers as x and x+1. The sum of these two numbers is x + (x+1) = 2x + 1. Given that the sum is 75, we have the equation 2x + 1 = 75. Solving for x, we find x = 37. Therefore, the two consecutive numbers are 37 and 38, and their sum is indeed 75.