Call the angle v: tan v = opp/ adj = 70/21 = 3.33; tan 73 = 3.26, tan 74 = 3.48
so 73 degrees is nearest.
Check: sin73 = opp/hyp so hyp is 70/sin 73 = 70/0.956 = 73.22.
Now use Pythagoras: does 73.22 squared equal 70 squared plus 21 squared?
In whole numbers 5329 = 4900 + 441? Not quite, but good enough for Wiki!
You can measure it. Or you can measure some other quantities (for examples, the lengths of the sides of a triangle), and calculate the angle using trigonometry.
67 degrees
The answer rounded to the nearest tenth is 25 meters.
I cannot answer this without knowing any more information. Finding the proper dimensions of a triangle without knowing the kind of triangle cannot really be done. Because it may be an isosceles triangle (every angle is equal) or it could be a 30-60-90 triangle etc.
Angle included by 50 and 34 = 21 degrees Angle included by 34 and 22 = 125 degrees Angle included by 22 and 50 = 34 degrees Total = 180 degrees
I don't see any isosceles triangle below.In general, the perimeter is the sum of the lengths of all sides. Note that in an isosceles triangle, two of the three sides have the same length.
Yes
This is not solvable in integers for a triangle. The solution to the nearest thousandth is: base = 9.132 and altitude = 6.132 Half base = 4.566 x alt 6.132 = 27.999, again to the nearest thousandth.
Using Pythagoras' theorem the length of the hypotenuse is 17.1 inches
Since an equilateral triangle has three congruent sides (and 3 congruent angles, each of 60⁰), the length of each side is 32/3 cm. If we draw one of the altitudes of the triangle, then a right triangle is formed where the side of a triangle is the hypotenuse, and the altitude is opposite to a 60 degrees angle. So we have, sin 60⁰ = altitude/(32/3 cm) (multiply by 32/3 cm to both sides) (32/3 cm)sin 60⁰ = altitude 9.2 cm = altitude
You can measure it. Or you can measure some other quantities (for examples, the lengths of the sides of a triangle), and calculate the angle using trigonometry.
Drop a perpendicular from apex to midpoint of base. You now have two Pythagorean triangles with hypotenuse 9 feet and one side 6 feet. Altitude = sqrt (81 - 36) = 3 root 5, so area of original triangle is 6 x 3 root 5 = 18 root 5 = 40.25 sq feet to the nearest hundredth
The hypotenuse measures 11.4 meters in length.
67 degrees
Area of a triangle = (base x Height)/2 = 7 ft x 15 ft/2 = 105/2 sq ft= 52.5 sq ft
Using trigonometry the area of the isosceles triangle 60 square cm and its perimeter is 48 cm both rounded to the nearest integer
in triangle def side de equals 5 and angle d equals 55 find fe