Since an equilateral triangle has three congruent sides (and 3 congruent angles, each of 60⁰), the length of each side is 32/3 cm.
If we draw one of the altitudes of the triangle, then a right triangle is formed where the side of a triangle is the hypotenuse, and the altitude is opposite to a 60 degrees angle. So we have,
sin 60⁰ = altitude/(32/3 cm) (multiply by 32/3 cm to both sides)
(32/3 cm)sin 60⁰ = altitude
9.2 cm = altitude
It has a perimeter of 12 units, an area of 7 (6.9282) square units and an altitude of 3.5 (3.4641) units.
Area = 0.5*base*altitude
For the equilateral triangle in Euclidean space(i.e, the triangles you see in general) median is the same as its altitude. So, both are of equal length.
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
Each side of the triangle is 45cm/3=15cm. The altitude divides the base into two equal segments of 7.5cm. This results in a right triangle with hypotenuse 15 cm and base 7.5cm. Pythagorus tells us a2+b2=c2 where a=altitude, b=base, c=hypotenuse. a2=c2-b2=152-7.52=225-56.25=168.75, a=12.99cm. Alternatively, the 3 angles of an equilateral triangle are all 60 degrees. The altitude divides one of these angles into two 30 degree angles. The cosine of 30 degrees is the opposite divided by the adjacent side. The adjacent side is the altitude. Thus a/c=cosine of 30 degrees, a=c X cos30 degrees = 15X0.866=12.99cm
28.75m
Given a perimeter of 18 units, the resulting altitude is 5.2 (5.19615) units.
Rhombus is an equilateral four sided form. If one side is 6, the perimeter is 4 x 6 = 24. The altitude makes no difference.
An equilateral triangle has 3 equal interior angles each of 60 degrees. There are two right angled triangles in an equilateral triangle. So we can use trigonometry to find the length of one side of the equilateral triangle then multiply this by 3 to find its perimeter. Hypotenuse (which is one side of the equilateral) = 15/sin 60 degrees = 17.32050808 17.32050808 x 3 = 51.96152423 Perimeter = 51.96152423 units.
It has a perimeter of 12 units, an area of 7 (6.9282) square units and an altitude of 3.5 (3.4641) units.
the height is 4.33 units cos 30 = .866 15 / 3 = 5 5 x .866 = 4.33
No. The altitude is smaller.
Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter
Given an altitude of 12 units, an equilateral triangle has side lengths of 13.9 (13.85641) units.
If the side is 11 then the perimeter is 44.The altitude is irrelevant. It can be anything less than 11, with no effect on the perimeter.
Area = 0.5*base*altitude
35.074 units2