Boyle's law states this fact.
This question refers to the combined gas law: (P1V1)/T1=(P2V2)/T2, where P is pressure, V is volume, and T is temperature in Kelvins.To solve for T1, rearrange the equation to isolate T1.T1=(P1V1T2)/(P2V2)
Boyle's law states this fact.
Boyle's Law is represented by the equation PV = k, where P is pressure, V is volume, and k is a constant when temperature is held constant. This law states that the pressure of a gas is inversely proportional to its volume.
The question is incomplete and unanswerable as written
This question refers to the combined gas law: (P1V1)/T1=(P2V2)/T2, where P is pressure, V is volume, and T is temperature in Kelvins.To solve for T1, rearrange the equation to isolate T1.T1=(P1V1T2)/(P2V2)
The general representation of the combined gas law is P1V1/T1 = P2V2/T2
P1v1=p2v2
This is the Boyle-Mariotte law !
To solve Boyle's Law equation for V2, first write the equation as P1V1 = P2V2. Then rearrange it to isolate V2 on one side, dividing both sides by P2 to solve for V2, which will be V2 = (P1 * V1) / P2.
Using the combined gas law, we can find the pressure by setting up the equation: P1V1/T1 = P2V2/T2. At STP, T1 = T2, so the equation simplifies to P1V1 = P2V2. Plugging in the values, we get P1 = (2.875 L * 1 atm) / 6.25 L = 1.38 atm.
P1V1 = P2V2, so 1480 litres in this case.
Possibly: P1V1 = P2V2 or: increase volume => lower pressure (thinking of the kinetic model)
Boyle's Law states that the pressure of a gas is inversely proportional to its volume, when the temperature is held constant. Mathematically, this relationship is expressed as P1V1 = P2V2, where P represents pressure and V represents volume.