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This question refers to the combined gas law: (P1V1)/T1=(P2V2)/T2, where P is pressure, V is volume, and T is temperature in Kelvins.
To solve for T1, rearrange the equation to isolate T1.
T1=(P1V1T2)/(P2V2)
Wiki User
∙ 6y ago
Wiki User
∙ 6y agot1 = P1v1t1/(p2v2).
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The equation p1v1 t1 equals p2v2 t2 is known as the what?
Avogardo's Law
Find the common ratio of the following geometric sequence 2.512 11.304 50.868 228.906 1030.077?
Formula for the nth term of general geometric sequence tn = t1 x r(n - 1) For n = 2, we have: t2 = t1 x r(2 - 1) t2 = t1r substitute 11.304 for t2, and 2.512 for t1 into the formula; 11.304 = 2.512r r = 4.5 Check:
What is the nth term formula of 100 96 92 and 88?
Since the difference of any two consecutive numbers (the common difference) is 4 (a constant), then this sequence is an arithmetic sequence. Let's take a look at this sequence: t1 = 100 t2 = t1 - 4 = 100 - 4 = 96 t3 = t2 - 4 = 96 - 4 = 92 t4 = t3 - 4 = 92 - 4 = 88 Thus, the formulas t1 = 100 and tn = t(n-1) - 4 gives a recursive definition for the sequence 100, 96, 92, 88.
Please list the sample space for flipping a coin and rolling a number cube with 1 2 3 4 5 and 6?
Flipping a coin: two possible outcomes, H or T. Rolling a die: six possible outcomes, 1, 2, 3, 4, 5, or 6. Flipping a coin and rolling a die: 12 possible outcomes. So the sample space has 12 outcomes such as, {H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6 }
What is the answer for finding the sum of the arithmetic sequence with a sigma notation with a 25 on top and t1 on the bottom then 5t-3 on the rightside?
To find the sum of 25 terms of these arithmetic sequence you can use the formula:Sn = (n/2)(a1 + an), where n is the number of terms in the sequence, a1 is the first term, and an is the last term of the sequence. In our case n = 25, so we need to compute a1 and a25.Since an = 5t - 3, thena1 = 5(1) - 3 = 5 - 3 = 2a25 = 5(25) - 3 = 125 - 3 = 122By substituting the values we know into the formula we have:S25 = (25/2)(2 + 122) = (25/2)(124) = 25 x 62 = 1,550Or you can use the formula:Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference.In order to find d, we need to find at least the value of 2 terms and subtract them.a1 = 2a2 = 5(2) - 3 = 10 - 3 = 7So d = 7 - 2 = 5By substituting the values we know into the formula we have:S25 = (25/2)[2(2) + (25 - 1)5]S25 = (25/2)(4+ 120) = (25/2)(124 = 25 x 62 = 1,550Thus, the sum of 25 terms of the given arithmetic sequence is 1,550.
The equation p1v1 t1 equals p2v2 t2 is known as the what?
Avogardo's Law
Which equation represent combined gas law?
The general representation of the combined gas law is P1V1/T1 = P2V2/T2
Why is you cold in the Alps?
Because it is so high up the air. Pressure up there is high and temperature therefore low if you use P1V1/T1= P2V2/T2
What law relates pressure and temperature at a constant volume as temperature increases pressure increases?
You can use the Ideal Gas Equation: pV=nRT or p1V1/T1 = p2V2/T2
True or false as heat is applied to a closed container containing a gas the pressure inside the container will decrease?
false; it will increase; Boyle's law says P1V1/T1 = P2V2/T2
What do you expect to happen to the volume of the gas if its pressure is doubled and its temperature is reduced to half?
From Boyle ideal gas law P1V1/T1 = P2V2/T2 so volume is reduced by a factor of 4
What do you expect to happen to the volume of a gas if its pressure is doubled and its temperature is reduced to half?
From Boyle ideal gas law P1V1/T1 = P2V2/T2 so volume is reduced by a factor of 4
What is the volume of gas at 250 degrees Celsius as compared with the volume at 0 degrees Celsius?
P1V1/T1 = P2V2/T2Assuming only temperature and volume are changing and pressure will be kept constant:V1/T1 = V2/T2Only Kelvin can be usedV1/273 = V2/523Assume the volume at 0 ºC is 1 unit thenV2 = 1.92 units
What is the volume of the gas at 250 degrees Celsius as compared with the volume at 0 degrees Celsius?
P1V1/T1 = P2V2/T2Assuming only temperature and volume are changing and pressure will be kept constant:V1/T1 = V2/T2Only Kelvin can be usedV1/273 = V2/523Assume the volume at 0 ºC is 1 unit thenV2 = 1.92 units
What is a fixed mass of gas is at a pressure of 7.00 atmospheres at 379 K in 2.00 liters what is the pressure at 425 K temperature and the same volume?
If it is an Ideal Gas, then you can use: P1V1/T1 = P2V2/T2, and since volume is constant, you have P1/T1 = P2/T2, where P is pressure and T is absolute temperature, and the subscripts refer to the 1st state and the 2nd state of the gas.So: (7.00 atm)/(379 K) = P2/(425 K), solve for P2 =(425 K)(7.00 atm)/(379 K)= 7.85 atm
To calculate an average speed you would use?
The distance traveled divided by the time it took. If you want the average speed between times t0 and t1 you could integrate the fuction of speed from t0 to t1 and divide by t1-t0.
To what temperature must 15 L of oxygen gas at 0 C be heated at 1 ATM pressure in order to occupy a volume of 23 L assuming that the pressure increases by 50 mm Hg?
Use the ideal gas law, PV = nRT when using L for Volume, pressure used must be in Kpa. Therefore P must be converted to Kpa and T must be converted to Kelvin since nR are the constants, nR for both will be the same therefore lets say P1 and V1 and T1 is the p and v and t before heating AND P2 V2 is the p and v after heating. P1V1/T1 = P2V2/T (find T) T = P2V2 / (P1V1/T1)
