A right triangle with legs of 7 and 11 units has a hypotenuse of: 13.04 units.
The length of both of the other legs is: 4.95
The square of the two legs is equal to the square of the hypotenuse. a2+b2 = c2 where a and b are the legs and c being the hypotenuse
The length of the hypotenuse of a right triangle with legs of lengths 5 and 12 units is: 13The length of a hypotenuse of a right triangle with legs with lengths of 5 and 12 is: 13
If the legs of a right triangle have measures of 9 and 12, the hypotenuse is: 15
The length of the hypotenuse of a right triangle with legs of 7 cm and 24 cm is: 25 cm
A right triangle with legs of 7 and 11 units has a hypotenuse of: 13.04 units.
the length of the hypotenuse is 10.63
Using Pythagoras' theorem the hypotenuse is 40 inches
The hypotenuse is 13.04 inches.
30cm
The Pythagorean theorem states that the length of the hypotenuse of a right triangle is the square root of the sum of the squares of the other two sides.[(24 in)^2 + (7 in)^2]^(1/2) = 25 in
If the legs of an isoceles right triangle are 7, then the hypotenuse is 9.9. Remember that in a right triangle, the sum of the squares of the sides adjacent to the right angle are equal to the square of the hypotenuse. In this case, the two sides are 7, so the square of the hypotenuse is 72 + 72, or 49 + 49, or 98. The hypotenuse, then, is the square root of 98, or about 9.9.
Use Pythagoras' theorem to find the hypotenuse which works out as 25cm Perimeter = 25+24+7 = 56cm
The length of both of the other legs is: 4.95
It is 7.62 units of length, approx.
13.04in