Use Pythagoras' theorem to find the hypotenuse which works out as 25cm
Perimeter = 25+24+7 = 56cm
Find the perimeter of a right triangle with legs measuring 3 and 4
With sides of 5 and 12, you can make a triangle with any perimeter you want between 24 and 34. If you call them "legs" because they are the sides of a right triangle, then the hypotenuse is 13, and the perimeter is 30.
The only formula you need is one that we're sure you already know.In every right triangle,(leg-A)2 + (leg-B)2 = (hypotenuse)2In this right triangle, the legs are equal, and the hypotenuse is 10.(leg)2 + (leg)2 = (10)22 times (leg)2 = 100Can you take it from there ?
If the legs are 3 and 4 then hypothenuse is 5 (SQRT (3 squared + 4 squared)) = 5) So perimeter is 3 + 4 + 5 = 12
The perimeter of a trapezoid is the sum of its bases and legs. The area of a trapezoid is the height times (base 1 + base 2) divided by 2
Find the perimeter of a right triangle with legs measuring 3 and 4
80 cm
With sides of 5 and 12, you can make a triangle with any perimeter you want between 24 and 34. If you call them "legs" because they are the sides of a right triangle, then the hypotenuse is 13, and the perimeter is 30.
The only formula you need is one that we're sure you already know.In every right triangle,(leg-A)2 + (leg-B)2 = (hypotenuse)2In this right triangle, the legs are equal, and the hypotenuse is 10.(leg)2 + (leg)2 = (10)22 times (leg)2 = 100Can you take it from there ?
If the legs are 3 and 4 then hypothenuse is 5 (SQRT (3 squared + 4 squared)) = 5) So perimeter is 3 + 4 + 5 = 12
A rectangle must have four right angles and parallel sides. Therefore, you can divide the rectangle into two equal right angle triangles along the diagonal. As the perimeter is the sum of all of the sides of the triangles that aren't a hypotenuse, each of one of the triangles' legs length would add up to to half the perimeter of the rectangle i.e. 7. The length of the hypotenuse is 5. With basic trigonometry you should recognise that this is a pythagorean triple, or in otherwords the hypotenuse is 5 and the lengths of the 'legs' are 3 and 4 Now that you now know the lengths of the legs of the right angle triangles, and the legs correspond with the sides of the rectangles, you can now calculate the area: A = 4*3 = 12 m2
You begin by finding the length of the unknown side. The square of the hypotenuse is equal to the sum of the squares of the two legs. Then once you have the lengths of all 3 sides, you adum all up, and you have the perimeter.
you're not right in the head.
The perimeter of a trapezoid is the sum of its bases and legs. The area of a trapezoid is the height times (base 1 + base 2) divided by 2
Legs are 'x' and '4x'.Hypotenuse is sqrt(17x2) = x sqrt(17)Perimeter = x [ 5 + sqrt(17) ]
Find the area and perimeter of a right ABC. The base is 17 cm and height is 21cm.
Perimeter = x-11+x+x which simplifies to 3x-11