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Call the width of the rectangle x. Call the length of the rectangle x + 2. The area of the rectangle would be the length times the width. We know this is 15 square inches. Set up the equation and solve for x.

(x +2)x = 15

x2 + 2x = 15

x2 + 2x - 15 = 0

Factor the quadratic equation:

(x - 3)(x + 5) = 0

x = 3 or x = -5

Since length can't be negative, discard the answer -5.

If x = 3, then the width is 3 and the length is x + 2 or 5. 5 x 3 = 15 which equals the area.

Q: The length of a rectangle is 2 inches more than its width the area of the rectangle is 15 square inches what are the length and width of the rectangle?

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The dimensions are: length = 15 inches and width = 7 inches Check: 15*7 = 105 square inches

They are: 3 inches and 5 inches respectively

A rectangle with one side that is double the length of the other side can be seen as two squares beside each other, that are half the area of the original rectangle, in this case 18 square inches / 2 = 9 square inches. The side of a square is the square root of the area, in this case the square root of 9 square inches, which is 3 inches. Now think about the rectangle again. What we just counted was the side of a square that made up one half of the rectangle you wanted to calculate the area of. So the shorter side of the rectangle is the same as our square, and the longer side is double the length. So the width of the rectangle is 3 inches, and the length is 2 * 3 inches = 6 inches. Or: Area = length x width (A=lw) Area = 18 (in2) Width = w Length = twice width (2w) 18 = (2w)w 18 = 2w2 9 = w2 3 = w The width is 3 in., the length (2w) is 6 in.

Let the width be (x-3) and the length be x: width*length = area (x-3)*x = 340 square inches x2-3x-340 = 0 Solving the above quadratic equation works out as: x = -17 or x = 20 it must be the latter because dimensions can't be negative. Therefore: length = 20 inches and width = 17 inches Check: 20*17 = 340 square inches

Area=Length*Width A=14 Inches*2 Inches A= 28 square inches or 28 in2

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The dimensions are: length = 15 inches and width = 7 inches Check: 15*7 = 105 square inches

Width of the rectangle: 33.6/8 = 4.2 inches

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They are: 3 inches and 5 inches respectively

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Area = Length * Width = 12*7 = 84 square inches.

A rectangle with one side that is double the length of the other side can be seen as two squares beside each other, that are half the area of the original rectangle, in this case 18 square inches / 2 = 9 square inches. The side of a square is the square root of the area, in this case the square root of 9 square inches, which is 3 inches. Now think about the rectangle again. What we just counted was the side of a square that made up one half of the rectangle you wanted to calculate the area of. So the shorter side of the rectangle is the same as our square, and the longer side is double the length. So the width of the rectangle is 3 inches, and the length is 2 * 3 inches = 6 inches. Or: Area = length x width (A=lw) Area = 18 (in2) Width = w Length = twice width (2w) 18 = (2w)w 18 = 2w2 9 = w2 3 = w The width is 3 in., the length (2w) is 6 in.