B2 for B = 9.
It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.
The question is a little unclear. If you mean: (A - B) x A2, then the answer is: A3 - (B x A2) (or, more simply, A3-BA2) If you mean: ((A - B) x A)2, then the answer is: (A2 - AB)2 which becomes A4 - 2A3B + A2B2
(a+b+c) 2=a2+ab+ac+ba+b2+bc+ca+cb+c2a2+b2+c2+2ab+2bc+2ca [ ANSWER!]
Prove (a+b)2 = a2 +b2 + 2ab It can be done by folding the paper. First fold one corner over and cut off excess to get a square piece of paper. Flatten out again. Fold a corner over most but not all of the way. The length of folded side is a. The rest of the side is b. The folded over area is a2 The unfolded strips along the sides are ab. There are 2 of them = 2ab The unfolded square remaining is b2 Therefore the total square (a+b)2 = a2 + 2ab + b2
(x3 - 8) is factored thus: (x - 2)(x2 + 2x + 4) The easiest way to do this is to remember the formula: (a3 - b3) = (a - b)(a2 + ab + b2)
b2 + ab - 2 - 2b2 + 2ab = -b2 + ab - 2 which cannot be simplified further.
b*ab = ab2 Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then ab2 = ab + b2 b = 1 + b/a would have to be true for all b. Counter-example: b = 2; a = 3 b(ab) = 2(3)(2) = 12 = ab2 = (4)(3) ab + b2 = (2)(3) + (2) = 10 but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2
ab-2ac+b^2-2bc
Proof that 2 equals 1.Given:a = 1b = 1Proof:a = ba2 = ab Multiply by aa2 - b2 = ab - b2 Subtract b2(a + b)(a - b) = b(a - b) Factor(a + b)(a - b)/(a - b) = b(a - b)/(a - b) Divide by (a - b)a + b = b2 = 1AnswerThe problem arises when you begin dividing by zero, in this case (a-b). It is easy to be distracted by the algebra, (a-b), and miss the fact that since a is equal to b, then (a-b) is equal to zero. As you probably know division by zero isn't allowed in mathematics.
(a-b)2 = (a-b)(a-b). You have to multiply each term in the left monomial by each term in the right monomial: a2 - ab - ab + b2 = a2 - 2ab + b2.
The GCF is 27b.
(a+b)2a2+b2+2ab(a-b)2=a2+b2-2ab(a+b)2=(a-b)2+4ab(a-b)2=(a+b)2-4aba2-b2=(a+b)(a-b)(a+b+c)2=(a+b+c+2ab+2bc+2cz)(a+b)3=a3+b3+3ab(a+b)(a-b)3=a3-b3-3ab(a-b)a3+b3=(a-b)(a2-ab+b2)a3-b3=(a+b)(a2+ab+b2)a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)(x+a)(x+b)=x2+x(a+b)+ab ==3a+10b-b+2a=5a+9by=mx+b is another one
It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.It means you multiply the binomial by itself. Multiplying polynomials requires multiplying every term of the first with every term of the second. For example, (a+b)2 = a2 + ab + ba + b2 = a2 + 2ab + b2.
Ba2(SO4)2
b2 - 7b - 6b = -4(-4)2 - 7(-4) - 6 = 16 +28 - 6 = 38
C = sqrt(C2) C2 = A2 + B2 - 2 A B cos(AB)
Some special cases that are relevant in practice are: (a + b)2 = a2 + 2ab + b2 (a - b)2 = a2 - 2ab + b2 (x + a)(x + b) = x2 + (a+b)x + ab