the answer would be exponent
the n in x indicating the number of factor of x is exponent
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x0 = x(n -n), which is equal to xn/xn by the law of powers. This obvoiusly = 1
Y=Xn Y/n=X
(x23)'=23x22 Generally, (xn)'=n*xn-1
A square matrix X is periodic if Xn = I, the identity matrix, and its period is n. If n = 1 then trivially, X = I, and Xk = I for all k. However, if n > 1, then Xn = I but Xk is not I for any k < n. Then Xna+b = Xna*Xb = Ia*Xb = Xb for all a. That is, X has a period of n. It can be shown that X, X2, ... , Xn-1 and I are distinct matrices that form a Group
not able to know what you mean?