exponent exponent
What you need to do is look for a common term throughout the expression. i.e. something that is multiplying everypart of the expression. In this case the common term is n. This common term goes on the outside the bracket: n(x-y) = xn - yn
The n in X" indicating the number of factors of X
Yes.
When the first number can divide the second without remainder. The formal definition would be as follows: For integers x and y, x is a factor of y if there exists an integer n such that y = n*x
n = 6, 12, 18, 24
the answer would be exponentthe n in x indicating the number of factor of x is exponent
yes, if you write x^n, then there are n x's multiplied together
nX in this case this says that n multiplys X by a factor of n Xn in this case this says that X is to the power of factor n not really another other case I can think of. Not sure what you are asking
xn- yn=(x - y)(xn-1 + xn-2y +xn-3y2 +. . .+x2yn-3+xyn-2 + yn-1)
This is represented as the algebraic expression xn/n or xn ÷ n.
x0 = x(n -n), which is equal to xn/xn by the law of powers. This obvoiusly = 1
xn+1 = 1/2 ( xn + N/xn )
Suppose that X1 = 1 and that Xn+1 = 1+ , for n > N Prove by induction that xn for n N
31. The pattern is likely xn = xn-1 + n + 6.
If by "xn" you mean ax^n then the answer is "a"
What you need to do is look for a common term throughout the expression. i.e. something that is multiplying everypart of the expression. In this case the common term is n. This common term goes on the outside the bracket: n(x-y) = xn - yn
It isn't. You're thinking of anything to the power zero. x0 = x(n - n) which equals xn divided by xn which equals 1.