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Let's lay out the known information in equations,

where B is the number of boys and G is the number of girls.

Then we express the number B in terms of G, which is twice

as much less 12, or (2G-12)

B + G = 51 , and

B = 2G - 12

Now, replace the B in the first equation with its value from the second equation

(2G - 12) + G = 51

Remove the brackets

2G - 12 + G = 51

Add 12 to both sides

2G + G = 51 + 12

3G = 63

Divide both sides by 3

G = 21

Now, to check if we're right,

Replace G in the first equation

B + 21 = 51

B = 30

If that's right then

30 = 2(21) - 12

30 = 42 - 12

And it is, so we know that there are 21 girls and 30 boys in ninth grade.

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sc.9102008hen

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2y ago

Let x= number of girls

2x-12 = number of boys

x+(2x-12) = 51

3x-12 = 51

3x = 63

x = 21

CHECK

21+2(21)-12 = 51

21+42-12 = 51

21+30 = 51

There are 21 girls in ninth grade

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Q: The number of boys in ninth grade is 12 less than twice the number of girls There are 51 students in ninth grade How many are girls?
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