The rectangle has Length = 16 cm and Width = 4 cm.
Perimeter = 2L + 2W = 2(16) + 2(4) = 32 + 8 = 40 cm
Area = L W = 16 x 4 = 64 cm2
The area of a square which has a perimeter of 40 meters is: 100 m2
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
15 feet.
40 cm Perimeter = 2 L + 2W = 30 + 10
The perimeter of this square measures 4 x 1 = 4 decimeters. As 1 decimeter = 10 centimeters then 4 decimeters = 4 x 10 = 40 centimeters.
The perimeter of a rectangle measuring 20x45 centimeters is (2*20) + (2*45) = 40 + 90 = 130 cm
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
yes
40
Let the width be x: 2(length+width) = perimeter 2(20+x) = 50 40+2x = 50 2x = 50 -40 2x = 10 x = 5 centimeters Check: 5+5+20+20 = 50 centimeters
Is it 82 or44 or 40 or28 or 26
The smallest is just over 40 units. At 40 units it is no longer a rectangle but a square. There is no largest perimeter.
100 cm2
40 meters.
Any length greater than 1 mile. The area of a rectangle is not sufficient to determine its perimeter.
10
Assuming you meant area of 40 cm2, the rectangle would need to be 40 cm x 1 cm