The length could be 3 cm (width = 1 cm), with a perimeter of 8 cm, which is not more than 72 cm. Or it could be 6 cm (w = 2 cm, perimeter = 16 cm).
The length of the rectangle is 27 meters and the width is 19 meters.
243 = 27 x 9 so perimeter is 2 x 36 ie 72.
L = 5W 2L + 2W = 72 ==> L + W = 36 Substitute L = 5W: 5W + W = 6W = 36. ==> W = 6, and L = 30. Area = 180
72 centimeters of what. im gonna assume the area is 72 cm. so it would be 72 sq cm your perimeter would be around 33.94 you need to take the squared root of 72. this gives the length of one side. then multiply this number by 4 since there are four sides to a square.
Perimeter = 720 mm or 72 cm
Perimeter is 36 mArea is 72 square m
The length could be 3 cm (width = 1 cm), with a perimeter of 8 cm, which is not more than 72 cm. Or it could be 6 cm (w = 2 cm, perimeter = 16 cm).
The length of the rectangle is 27 meters and the width is 19 meters.
The rectangle is 9 inches wide X 27 inches long. Clue: width is X; length is 3 times width (3X). Perimeter is width plus length times two (X + 3X times 2 = 8X). 8X = 72; X = 9. 3X = 27. Proof: 9 + 9 (2sides) +27 + 27 (2 lengths) = 72.
Length = 24 cm and width = 12 cm Check: 2*(24+12) = 72 cm
Area = (length) x (width)72 = (24) x (width)Width = 72/24 = 3Perimeter = 2 x (length + width) = 2 x (24 + 3) = 2 x (27) = 54
243 = 27 x 9 so perimeter is 2 x 36 ie 72.
72
It is: 12 units in length
The area is 72 The dimensions would be 6x12 6 * 2 + 12 * 2 = 36
length is 8, width is 4L = W + 42L + 2W = 722(W + 4) + 2W = 722W + 8 + 2W = 724W = 72 - 8W = 64 / 4W = 4L = 4 + 4L = 8