Best Answer

We don't know. The perimeter doesn't uniquely define the dimensions.

It could be:

1 x 35

2 x 34

3 x 33

4 x 32

5 x 31

10 x 26

15 x 21

15.39 x 20.61

.

.

etc.

All of these rectangles have a perimeter of 72.

Q: The perimeter of a rectangle is 72 what are the length and width?

Write your answer...

Submit

Still have questions?

Continue Learning about Algebra

The length could be 3 cm (width = 1 cm), with a perimeter of 8 cm, which is not more than 72 cm. Or it could be 6 cm (w = 2 cm, perimeter = 16 cm).

The length of the rectangle is 27 meters and the width is 19 meters.

243 = 27 x 9 so perimeter is 2 x 36 ie 72.

L = 5W 2L + 2W = 72 ==> L + W = 36 Substitute L = 5W: 5W + W = 6W = 36. ==> W = 6, and L = 30. Area = 180

If l is the length and w is the width, we get the following two equations: l=3w-4 AND 2l+2w=64. Plugging l from the first equation into the second equation and solving for w, we get: 2*(3w-4) + 2w=64 8w-8=64 8w=72 w=9 Using w=9 and the first equation to find l, we get: l=3*9-4=23.

Related questions

Perimeter = 720 mm or 72 cm

Perimeter is 36 mArea is 72 square m

The length could be 3 cm (width = 1 cm), with a perimeter of 8 cm, which is not more than 72 cm. Or it could be 6 cm (w = 2 cm, perimeter = 16 cm).

The length of the rectangle is 27 meters and the width is 19 meters.

The rectangle is 9 inches wide X 27 inches long. Clue: width is X; length is 3 times width (3X). Perimeter is width plus length times two (X + 3X times 2 = 8X). 8X = 72; X = 9. 3X = 27. Proof: 9 + 9 (2sides) +27 + 27 (2 lengths) = 72.

Length = 24 cm and width = 12 cm Check: 2*(24+12) = 72 cm

Area = (length) x (width)72 = (24) x (width)Width = 72/24 = 3Perimeter = 2 x (length + width) = 2 x (24 + 3) = 2 x (27) = 54

243 = 27 x 9 so perimeter is 2 x 36 ie 72.

72

It is: 12 units in length

The area is 72 The dimensions would be 6x12 6 * 2 + 12 * 2 = 36

length is 8, width is 4L = W + 42L + 2W = 722(W + 4) + 2W = 722W + 8 + 2W = 724W = 72 - 8W = 64 / 4W = 4L = 4 + 4L = 8