We don't know. The perimeter doesn't uniquely define the dimensions.
It could be:
1 x 35
2 x 34
3 x 33
4 x 32
5 x 31
10 x 26
15 x 21
15.39 x 20.61
.
.
etc.
All of these rectangles have a perimeter of 72.
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The length could be 3 cm (width = 1 cm), with a perimeter of 8 cm, which is not more than 72 cm. Or it could be 6 cm (w = 2 cm, perimeter = 16 cm).
The length of the rectangle is 27 meters and the width is 19 meters.
243 = 27 x 9 so perimeter is 2 x 36 ie 72.
L = 5W 2L + 2W = 72 ==> L + W = 36 Substitute L = 5W: 5W + W = 6W = 36. ==> W = 6, and L = 30. Area = 180
If l is the length and w is the width, we get the following two equations: l=3w-4 AND 2l+2w=64. Plugging l from the first equation into the second equation and solving for w, we get: 2*(3w-4) + 2w=64 8w-8=64 8w=72 w=9 Using w=9 and the first equation to find l, we get: l=3*9-4=23.