95 degrees (hint: construct the circumcircle of BCD
If the angle opposite the side of 12.5 meters is 30 degrees then use the sine ratio to find the hypotenuse which works out as 25.0 meters.
Angle A + Angle B + Angle C = 180 degrees. 30+90+C=180 120+C=180 C=60 degrees.
22, The shortest side is opposite the smallest angle. As it is a right angle triangle, the Sine ratio can be used: Sine = opposite/hypotenuse ⇒ hypotenuse = opposite/sine = 11/sine 30o = 11 ÷ 1/2 = 22
if the interior angle is 150 the exterior angle equals 30. since exterior angle equals 360/ by number of sides the number of sides equals 360/30 which equal 12
Yes, the sine decreases, and so does the tangent.
An angle with 30 degrees is an acute angle.
Rearrange the sine ratio of sine = opposite/hypotenuse: hypotenuse = opposite/sine hypotenuse = 12/sine 30 degrees = 24 Therefore the hypotenuse is 24 units in length.
A right angle is 90 degrees and a 1/3 of 90 degrees equals 30 degrees
sine of 30 degrees
The trigonometric function of an angle gives a certain value The arc trigonometric function of value is simply the angle For example, if sin (30 degrees) = 0.500 then arc sine ( 0.500) = 30 degrees
The compliment of an angle is found by taking 90 degrees minus the known angle. Therefore, you take 90 minus 30 which equals 60 degrees.
If you know the angle's sine, cosine, or tangent, enter it into the calculator and press <inverse> sine, cosine, or tangent. On MS Calc, in Scientific Mode, using Degrees, enter 0.5, then check Inv and the press sin. You should get 30 degrees. The other functions work similarly.
Sin30 degrees is 0.50000
When you subtract theta from 180 ( if theta is between 90 degrees and 180 degrees) you will get the reference angle of theta; the results of sine theta and sine of its reference angle will be the same and only the sign will be different depends on which quadrant the angle is located. Ex. 150 degrees' reference angle will be 30 degrees (180-150) sin150=1/2 (2nd quadrant); sin30=1/2 (1st quadrant) 1st quadrant: all trig functions are positive 2nd: sine and csc are positive 3rd: tangent and cot are positive 4th: cosine and secant are positive
Two sine waves, one with zero crossing at 30 degrees, the other with zero crossing of 45 degrees, have a relative phase angle of 15 degrees. Simply subtract the two angles from each other.
9 degrees