When you subtract theta from 180 ( if theta is between 90 degrees and 180 degrees) you will get the reference angle of theta; the results of sine theta and sine of its reference angle will be the same and only the sign will be different depends on which quadrant the angle is located.
Ex. 150 degrees' reference angle will be 30 degrees (180-150)
sin150=1/2 (2nd quadrant); sin30=1/2 (1st quadrant)
1st quadrant: all trig functions are positive
2nd: sine and csc are positive
3rd: tangent and cot are positive
4th: cosine and secant are positive
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96 degrees Let theta represent the measure of the angle we are trying to find and theta' represent the measure of its supplement. From the problem, we know: theta=theta'+12 Because supplementary angles sum to 180 degrees, we also know: theta+theta'=180 Substituting the value from theta in the first equation into the second, we get: (theta'+12)+theta'=180 2*theta'+12=180 2*theta'=180-12=168 theta'=168/2=84 Substituting this value for theta' back into the first equation, we get: theta+84=180 theta=180-84=96
Every multiple of 180 degrees, beginning with zero.
Sine of an angle cannot be 2, as you must be knowing, sin90=1, u may conclude that sin180=2. but 180 degree cannot be an angle of a triangle,
180 minus interior angle = exterior angle
180 minus interior angle = exterior angle