47 Impossible problem!
The number is 36
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
after 11yrs.
Possibility of two digit no whose sum is 11 Are 29,38,47,56,65,74,83,92 Subract 45 to each no mentioned above -16,-7,2,11,20,29,38,47 See after 6th comma 83 and 38 Reverse of 83 is 38. The no 38 is 45 less than 83. Original no is=83
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,91 Now add 9 to each no mentioned above 27,36,45,54,63,72,91,100 See after third comma 45 and 54. If you reverse 45 it will be 54. which is 9 more than 45. So original no is 45
39
The number is 36
17
192
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
five digits number when you multiply by four is the same the number when you reversed it is 21978*4 = 87912
To total 17 the two digits must be 8 and 9! The original number was 98.
An eight digit number with one zero cannot remain the same when its digits are reversed. It must have an even number of 0s.
after 11yrs.
11yrs.
The number you are looking for is 12. Reversing the digits gives you 21 75% of 12 is 9 12 + 9 = 21
Find a four digit number whose digits will be reversed when multiplied by nine?