17
Any two digit number in which: (a) the units digit is not 0, and (b) the two digits are different will form a new 2-digit number when the digits are interchanged.
Not necessarily. Consider 444. The digits are not different. The first and second digits are not multiples of 3 The first digit is not greater than the second digit. In spite of all that, 444 is a 3-digit number
Multiplying a 2-digit number by a 1-digit number involves multiplying the digits in the ones and tens place and then adding the products. Similarly, multiplying a 3-digit number by a 1-digit number follows the same principle, where you multiply the digits in the ones, tens, and hundreds place and then add the products. The main difference is that in the latter case, you are dealing with three sets of digits to multiply and add, whereas in the former, you only have two sets of digits.
Six.
Any 5-digit number is greater than a 4-digit one.
The number is 36
47 Impossible problem!
Find a four digit number whose digits will be reversed when multiplied by nine?
192
To total 17 the two digits must be 8 and 9! The original number was 98.
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
45
An eight digit number with one zero cannot remain the same when its digits are reversed. It must have an even number of 0s.
"If the units digit and the hundreds digit of the number 513 were reversed..." 315 'find the sum of the original number and the new number." 513+315=828
A) If a number has two digits, then the sum of its digits is less than the value of the original two-digit number.
100000 2847239582
2178