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Best Answer
Let the numbers be m & m+1 (consecutive)
Hence their squares are
m^2 & ( m + 1)^2 => m^2 & m^2 + 2m + 2
Hence
Their sum is
m^2 + m^2 + 2m + 1 = 85
2m^2 + 2m - 84 = 0
m^2 + m - 42 =0
Factor
(m + 7)(m - 6) = 0
Hence the numbers are 6 & 7 .
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