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Let's label one of the numbers with x, and the other number with y. So,

x + y = 25

4x - 12 = 2y + 16 add 12 and subtract 2y to both sides of the second equation; x + y = 25

4x - 2y = 16 +12 multiply by -4 the first equation; -4x - 4y = -100

4x - 2y = 16 +12 add both equations in order to eleminate x; 0 - 6y = -72 multiply by -1 to both sides;

6y = 72 divide by 6 both sides;

y = 12 Substitute 12 for y into the first equation;

x + y = 25

x + 12 = 25 subtract 12 to both sides;

x = 13

Thus, the numbers are 13 and 12. Check:

13 + 12 = 25

4(13) -12 = 2(12) +16 ?

52 -12 = 24 + 16 ?

40 = 40

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Q: The sum of two numbers is twenty-five Twelve less than four times one of the numbers is sixteen more than twice the other number?
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