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How do you write a numerical or variable expression for the value in cents of n nickels?
answer: 5n
If you have 2.35 in dimes and nickels and you have one more dime than nickels how many of each do you have?
Let's represent the number of nickels as "N" and the number of dimes as "D." Since you have $2.35 in total, we can set up the equation 0.05N + 0.10D = 2.35. Additionally, we know that there is one more dime than nickels, so we have the equation D = N + 1. By substituting the second equation into the first and solving simultaneously, we find that N = 9 and D = 10. Therefore, you have 9 nickels and 10 dimes.
A cash register contains 12.50 and there are only nickels dimes and quarters There are twice as many dimes as nickels and twice as many quarters as dimes How many quarters are in the cash register?
Nickles - 10 $0.50dimes - 20 $2.00quarters - 40 $10.000.50+2.00+10.00 = $12.50 containing 40 quarters---Here's how to solve this with Algebra :Let N be the number of nickels, so that2N is the number of dimes, and2(2N) or 4N is the number of quarters.A nickel is 5 cents, a dime is 10 cents, and a quarter is 25 cents,and the total in the cash register is $12.50Multiplying by their cents values, we have5(N) plus 10(2N) plus 25 (4N) = 12505N + 20N + 100N = 1250125 N = 1250N= 10So the number of nickels is 10, dimes 20, and quarters 40.
You save 42 nickels and dimes that total 3.35 how many nickels and dimes do you save?
This problem can be solved using a system of equations.If we call the number of nickles n and the number of dimes d, we can write the following two equations:n + d = 42 (The number of nickels and dimes is 42).05n + .1d = 3.35 (5 cents for every nickel plus 10 cents for every dime is $3.35)Then:n + d = 425n + 10d = 335 (Switch to cents instead of dollars, gets rid of decimals)n = 42 - dWe have now just defined n in terms of d. Now every time you see n in the second equation, you can replace it. This is called substitution.5n + 10d = 335 (from above)5(42 - d) + 10d = 335 (substituting for n)Follow through with the algebra, and d (# of dimes) = 25, then there must be 17 nickels.25 dimes, 17 nickels
You piggy bank has all nickels and quarters. You count up the coins and find out that there are 64 coins and you have a total of 7.40. How many of each type of coin do you have?
The idea is to write two equations, one for the number of coins, one for the amount of money. Then solve the equations.Assuming "n" is the number of nickels, and "q" the number of quarters, the equations for the coins, of course, is quite simply: n + q = 64 And the equation for the money (I'll use cents; you can just as well use dollars if you prefer): 5n + 25q = 740 You can solve the first equation for "n", then replace that in the second equation.
