Q: The volume of a circular cylinder varies directly with the height of the cylinder and with the square of the cylinder's radius If the height is halved and the radius is doubled then the volume will be?

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The volume is doubled.

If the radius and height of a cylinder are both doubled, then its surface area becomes 4 times what it was originally, and its volume becomes 8 times as much.

Two times larger.

V = (pi)*R2*H if you double the radius then put 2R in place of R in the formula: V = (pi)*(2R)2*H V = 4pi*R2*H So the volume will increase 4 fold if you double the cylinder's radius.

If the length of each side is doubled, then the perimeter is also doubled.

Related questions

The volume of the cylinder would be doubled.

The volume will be doubled.

quadrupled. :)

If both the speed of the body and the radius of its circular path are doubled, the centripetal force required to keep the body moving in a circular path will quadruple. This is because centripetal force is directly proportional to the square of the speed and inversely proportional to the radius of the circular path.

4

The volume is doubled.

Volume doubles

Volume doubles

If the radius and height of a cylinder are both doubled, then its surface area becomes 4 times what it was originally, and its volume becomes 8 times as much.

If the speed of the centripetal force is doubled, the required centripetal force also doubles to keep the object moving in a circular path at that speed. The centripetal force needed is directly proportional to the square of the speed, so doubling the speed results in a quadrupling of the centripetal force required.

Yes.

The centripetal force required for a body in uniform circular motion is given by Fc = (mv^2) / r, where m is the mass, v is the velocity, and r is the radius of the circle. If the mass is doubled, the centripetal force needed will also double based on the equation.