6 to 1
729:1
6^3=216 The volume of a cone is 1/3*pi*r^2*h. If r and h are each 6 times larger (as they are in this problem), then the volume is 6*6*6 times larger.
8 27
it depends whether the area of the circles ontop are the same (pie x diameter) if so, yes. if not, no. 64:27 .
I guess you mean the ratio of the areas; it depends if the 2 rectangles are "similar figures"; that is their matching sides are in the same ratio. If they are similar then the ratio of their areas is the square of the ratio of the sides.
16/9
729:1
If the ratio is 2 : 7 then the volumes are in the ratio 8 : 343.
ratio of volumes is the cube of the ratio of lengths radii (lengths) in ratio 3 : 4 → volume in ratio 3³ : 4³ = 27 : 64
It is 8 : 343.
It is 27 : 343.
343:1
343:1
You cannot because the volumes of the cones also depend on their heights.
7:3
Volume of a sphere of radius r: V = 4pi/3 x r3 If the ratio of the radii of two spheres is 23,then the ratio of their volumes will be 233 = 1,2167
Not enough information has been given but the volume of a cone is 1/3*pi*radius squared *height and its base area is pi*radius squared