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V=5*5+10*x, where V is the value in cents.

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Q: Type the equation that represents the value of 5 nickels and x dimes?
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A vending machine takes only nickels and dimes. There are 5 times many dimes as nickels in the machine. The face value of the coins is 4.40. How many of each coin are in the machine?

40 Dimes and 8 Nickles


How many coins of each type does Cameron have if he has 4.50 in nickels and dimes in his piggy bank and the number of dimes is twice the number of nickels?

In order to eliminate the decimal point, let us work with cents. So, let $ 4.50 = 450 cents. If the number of nickels is x, then the value of x nickels is 5x cents. Since the number of dimes is twice the number of nickels, then we can write the number of dimes as 2x, and the value of 2x dimes as 10(2x) or 20x cents. So we have: 5x + 20x = 450 25x = 450 divide by 25 to both sides x = 18 the number of nickels 2x = 2 x 18 2x = 36 the number of dimes Thus, Cameron has 18 nickels and 36 dimes. Check: 18 nickels = 18 x 5 cents = 90 cents or $ 0.90 36 dimes = 36 x 10 cents = 360 cents or $ 3.60 0.90 + 3.60 = 4.50? 4.50 = 4.50 True


If you have 2.35 in dimes and nickels and you have one more dime than nickels how many of each do you have?

Set up your equations based upon the following: Let N = number of nickles. Let N + 1 = number of dimes. Let 5N = the value (in cents) of all the nickles. Let 10(N + 1) = the value (in cents) of all the dimes. Let 235 = the total value (in cents) of all the coins (nickles and dimes). In English, the value of the dimes plus the value of the nickles equals the total value of the coins. Algebraically, we write: 5N + 10(N + 1) = 235 The distributive law of multiplication lets us rewrite that this way: 5N + 10N + 10 = 235 Grouping lets us write that this way: 15N + 10 = 235 Subtracting 10 from both sides of the equation yields: 15N = 225 Dividing both sides by 15 yields: N = 15 So, we have 15 nickles and 15 + 1, or 16, dimes.


The value 11.7 represents the of the graph of the following linear regression equation?

slope


What letter represents slope on slope-intercept equation?

The equation of line in terms of y , x coordinates and intercept can be written as : y= m x+ c where m is the slope of the equation and the c is value of intercept.

Related questions

Pat has 5.80 in nickels and dimes. If there are 73 coins in all how many of them are dimes?

Let's say the number of dimes Pat has is D. The number of nickels would then be 73 - D. The total value of the dimes is 10D cents, and the total value of the nickels is 5(73 - D) cents. Since the total value is 580 cents (5.80 dollars), we can set up the equation 10D + 5(73 - D) = 580. Solving this equation would give us the value of D, which represents the number of dimes Pat has.


How many dimes in 40 nickels?

There are no dimes in nickels, but 20 dimes have the same purchasing value as 40 nickels have.


How many dimes are in 50 nickels?

There are no dimes in nickels. But 25 dimes have the same monetary value as 50 nickels have.


What are nickels and dimes in value?

Nickels are worth five cents and dimes are worth ten.


If Andy has 16 coins. Some of them are dimes and some are nickels. The combined value of his dimes and nickels is 1.35. How many dimes and nickels does he have?

11 dimes and 5 nickels.


Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?

Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?


10 coins consistinig of nickels and dimes equal 80 cents how many coins does she have?

You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.


How many nickels equal 7 dimes?

Two nickels equal the value of one dime, therefore fourteen (14) nickels would equal the value of seven (7) dimes.


Nick has 35 coins consisting of dimes and nickels If the value of the coins is 3.10 then how many dimes does he have?

he has 27 dimes. to add on, he has 8 nickels to make your total of 3.10


Which stack has the most value a stack of nickels 150 mm high or a stack of dimes 50 mm high?

Nickels, dimes are only slightly smaller in height than nickels.


How many dimes does Joe have if a collection of nickels and dimes that is worth 6.05 If the number of dimes was doubled and the number of nickels was decreased by 10 the value coins would be 9.85?

Ten it each group.


Jimmy had 15 coins in his pocket they were dimes and nickels the total value of the coins was 1.30 how many dimes did he have in his pocket?

11 dimes.