3x-8y=-1
-2x+6y=1
Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
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Without any equality signs the given expression can't be considered to be equations.
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Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
with ur partner
y=3x-4 y=-2x+1
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(0,7)
Do you mean: 4x+7y = 47 and 5x-4y = -5 Then the solutions to the simultaneous equations are: x = 3 and y = 5
How to solve a system of linear equations 1. arrange all of them in standard form. standard form has all variables in the same order beginning with the lowest power variables on the left and ending with the highest power variables on the right. This will be equal to the number without a variable on the right side of the equation. If there are missing variables or numbers, put in a zero in it's place. 2. Using a TI-83: Press these keys: 2nd, matrix, >>, enter. Type how many rows your matrix has (if you have 3 equations, you need 3 rows). Press enter. Type how many columns your matrix has (if you have x^3, x^2, and x on one side of the equal sign, you need 3 columns). Press enter. Begin entering your data, ignoring the number on the right side of the equals sign. When finished, press 2nd, quit. 3. Press 2nd, matrix, >>, down, enter. Using the example from above with the 3 equations, you now need a 3x1 matrix. When finished entering data, press 2nd, quit. 4. Press 2nd, matrix. Hilight the 3x3 matrix you created, press enter. Press the x^-1 key. Press 2nd, matrix. Hilight the 3x1 matrix, press enter, enter. And wall-a, there you have your answers!! If you were to solve it by hand, just solve two of the equations for a different variable and plug the solved equations into the unsolved equation and solve. This way can get hairy, but it also works fine.
It works out that x = 6 and y = 3 or as (6, 3)
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