The equation in slope-intercept form would be y=-2x
Y+2 = 2 (x-3)
What is the equation of the vertical line passing through (-5,-2)
For a straight line equation to be parallel to another straight line equation they both must have the same slopes but different y intercepts.
Points: (3, 2) and (-9, 6) Slope: -1/3 Equation: 3y = -x+9
Slope: -35 passing through (-5, -1) Equation: y = -35x-176
If you mean: y = 6x-4 then the parallel equation is y = 6x+10
y=-x
what
If you mean: y = -x-3 passing through point of (-1, 3) Then the equation of the parallel line is: y =-x+2
The parallel equation works out as: 4y = 3x+1 which can be expressed in the form of 3x-4y+1 = 0
Y+2 = 2 (x-3)
If you mean: (9, -12) then the equation is y = -12 which is a straight line parallel to the x axis passing through (0, -12)
solve the equation for y to get the slope.y=-2x-1/2substitute (3,3) into the equation/3=2(3)+band solve for b.-3=+by=2x-3 is the equation with the same slope(parallel) and goes through (3,3)
What is the equation of the vertical line passing through (-5,-2)
For a straight line equation to be parallel to another straight line equation they both must have the same slopes but different y intercepts.
The equation y = -2.5 represents a horizontal line on the Cartesian plane passing through the point (-2.5, 0). This line is parallel to the x-axis and has a slope of 0. The solution to this equation is all real numbers on the y-axis that have a value of -2.5.
The equation of a vertical line passing through the point (a, b) is x a.