In this equation, 1 multiplied by any number will equal 5. Therefore, the blank should be filled with the number 5, as 1 x 5 = 5. This is a simple multiplication problem where the multiplicand is 1 and the product is 5.
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1 = 3^(0) 3 = 3^(1) 9 = 3^(2) x = 3^(3) 81 = 3^(4) Notice that the indices rise term by term. Hence x = 3^(3) = x = 27
1 x 25, 5 x 5, 25 x 1
x^(-5/3) = 4 1/x^(5/3) = 4 x^(5/3) = 1/4 [x^(5/3)]^(3/5) = (1/4)^(3/5) x = 1/4^(3/5) or, x = 4^(-3/5) Check: x^(-5/3) = 4 [4^(-3/5)]^(-5/3) = 4 ? 4 ^(15/15) = 4 ? 4^1 = 4 ? 4 = 4
x-4x=5 (1)x-(4)x=5 (-3)x=5 x= 5/(-3) x= -5/3
First, you draw a horizontal line which is like your x-axis. Then, lets say your data ranges from 1-5, you number the line 1-5. Next, you put one x above each number for each time that number occurs.EXAMPLE: xx5 2 1 3 5 x x x x2 3 5 1 1 x x x x4 2 4 3 1 x x x x x2 3 5 1 1 x x x x x1 2 3 4 5