1 = 3^(0) 3 = 3^(1) 9 = 3^(2) x = 3^(3) 81 = 3^(4) Notice that the indices rise term by term. Hence x = 3^(3) = x = 27
1 x 25, 5 x 5, 25 x 1
x^(-5/3) = 4 1/x^(5/3) = 4 x^(5/3) = 1/4 [x^(5/3)]^(3/5) = (1/4)^(3/5) x = 1/4^(3/5) or, x = 4^(-3/5) Check: x^(-5/3) = 4 [4^(-3/5)]^(-5/3) = 4 ? 4 ^(15/15) = 4 ? 4^1 = 4 ? 4 = 4
First, you draw a horizontal line which is like your x-axis. Then, lets say your data ranges from 1-5, you number the line 1-5. Next, you put one x above each number for each time that number occurs.EXAMPLE: xx5 2 1 3 5 x x x x2 3 5 1 1 x x x x4 2 4 3 1 x x x x x2 3 5 1 1 x x x x x1 2 3 4 5
x2 - 4x - 5 = zero( x - 5 ) ( x + 1 ) = zerox - 5 = zero ...... X = 5x + 1 = Zero ...... X = -1
(6v) x ___ = 5. In order for this expression to be true V would have to be 1/6th. 6(1/6) x ____ = 5 1 x ____ = 5 1 x 5 = 5.
1 x 525, 3 x 175, 5 x 105, 7 x 75, 15 x 35, 21 x 25 = 525
5.2 x 5 = 26 13 x 2 = 26
There are an infinite number of solutions. Blank1 = 1 and blank2 = 15 B1 = -1 and B2 = -15 B1 = 2 and B2 = 7.5 B1 = 3 and B2 = 5 B1 = 1.1 and B2 = 15/1.1 etc, etc.
It is suppose to be 7 1/5 and 72/ 10 and then fill in the blank with < > =
12 equals 3x(4) equals 6x(2) equals (12)x1
3-x=5 -x=2 x=-2 -2 3-(-2)=5 3+2=5 answer is negative 2
5 x 8 = 40 so the answer is 5
3/5 x ___ = 2/5 I think this is the question. If the blank can be represented by the letter a, then: 3/5 x a = 2/5 3a/5=2/5 3a=2 a=2/3 Let's test the answer: 3/5 x 2/3 = 2/5 6/15 = 2/5 Let's pull out the calculator: 6/15=0.4 2/5=0.4 So I guess the blank is 2/3, or 0.666666666666...
Well, darling, 380 can be equal to a lot of things depending on the context. It could be the sum of 190 and 190, the product of 38 and 10, or the result of subtracting 20 from 400. So, the possibilities are endless, just like my wit.
.5
x**2+0x-25 --> (x+5)(x-5)