1 = 3^(0) 3 = 3^(1) 9 = 3^(2) x = 3^(3) 81 = 3^(4) Notice that the indices rise term by term. Hence x = 3^(3) = x = 27
1 x 25, 5 x 5, 25 x 1
x^(-5/3) = 4 1/x^(5/3) = 4 x^(5/3) = 1/4 [x^(5/3)]^(3/5) = (1/4)^(3/5) x = 1/4^(3/5) or, x = 4^(-3/5) Check: x^(-5/3) = 4 [4^(-3/5)]^(-5/3) = 4 ? 4 ^(15/15) = 4 ? 4^1 = 4 ? 4 = 4
First, you draw a horizontal line which is like your x-axis. Then, lets say your data ranges from 1-5, you number the line 1-5. Next, you put one x above each number for each time that number occurs.EXAMPLE: xx5 2 1 3 5 x x x x2 3 5 1 1 x x x x4 2 4 3 1 x x x x x2 3 5 1 1 x x x x x1 2 3 4 5
x2 - 4x - 5 = zero( x - 5 ) ( x + 1 ) = zerox - 5 = zero ...... X = 5x + 1 = Zero ...... X = -1
(6v) x ___ = 5. In order for this expression to be true V would have to be 1/6th. 6(1/6) x ____ = 5 1 x ____ = 5 1 x 5 = 5.
1 x 525, 3 x 175, 5 x 105, 7 x 75, 15 x 35, 21 x 25 = 525
5.2 x 5 = 26 13 x 2 = 26
There are an infinite number of solutions. Blank1 = 1 and blank2 = 15 B1 = -1 and B2 = -15 B1 = 2 and B2 = 7.5 B1 = 3 and B2 = 5 B1 = 1.1 and B2 = 15/1.1 etc, etc.
It is suppose to be 7 1/5 and 72/ 10 and then fill in the blank with < > =
12 equals 3x(4) equals 6x(2) equals (12)x1
3-x=5 -x=2 x=-2 -2 3-(-2)=5 3+2=5 answer is negative 2
5 x 8 = 40 so the answer is 5
3/5 x ___ = 2/5 I think this is the question. If the blank can be represented by the letter a, then: 3/5 x a = 2/5 3a/5=2/5 3a=2 a=2/3 Let's test the answer: 3/5 x 2/3 = 2/5 6/15 = 2/5 Let's pull out the calculator: 6/15=0.4 2/5=0.4 So I guess the blank is 2/3, or 0.666666666666...
1 x 380, 2 x 190, 4 x 95, 5 x 76, 10 x 38, 19 x 20.
.5
x**2+0x-25 --> (x+5)(x-5)